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Chapter 15: Q19. (page 570)

Question: Draw the structure of the four allylic halides formed when 3-methylcyclohexene undergoes allylic halogenation with NBS + hν.

Short Answer

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Answer

Step by step solution

01

Halogenation

Treatment of compound with the halogen yield substituted product. It involves the presence of light.

02

Formation of products

The reaction of methylcyclohexene with NBS in the presence of light. The reaction is shown below:

Formation of products

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Most popular questions from this chapter

Question: Draw the six products (including stereoisomers) formed when A is treated with NBS + hv.

Question: Draw the product(s) formed when each alkene is treated with either [1] HBr alone; or [2] HBr in the presence of peroxides.

a.

b.

c.

Question: Rank the following radicals in order of increasing stability.

Consider the following Bromination:

(a) Calculate ΔH° for this reaction by using the bond dissociation energies in Table 6.2.

(b) Draw out a stepwise mechanism for the reaction, including the initiation, propagation, and termination steps.

(c) Calculate ΔH° for each propagation step.

(d) Draw an energy diagram for the propagation steps.

(e) Draw the structure of the transition state of each propagation step

Question: Show all steps and reagents needed to convert cyclohexane into each compound: (a) the two enantiomers of trans-1,2-dibromocyclohexane; and (b) 1,2-epoxycyclohexane.
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