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Chapter 15: Q17. (page 570)

Question: Draw the products of each reaction.

a.

b.

c.

Short Answer

Expert verified

Answer

a.

b.

c.

Step by step solution

01

Allylic bromination with NBS

The two steps involved in this reaction are; initiation and propagation.

02

Formation of products

a.

The reaction is shown below:

Product formation in a

b.

The reaction is shown below:

Product formation in b

c.

The reaction is shown below:

Product formation in c

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Most popular questions from this chapter

Question: As we will learn in Chapter 30, styrene derivatives such as A can be polymerized by way of cationic rather than radical intermediates. Cationic polymerization is an example of electrophilic addition to an alkene involving carbocations.

a. Draw a short segment of the polymer formed by the polymerization of A.

b. Why does A react faster than styrene (C6H5CH=CH2)in a cationic polymerization?

Question: Five isomeric alkanes (Aโ€“E) having the molecular formula C6H14 are each treated with Cl2 + hv to give alkyl halides having molecular formula C6H13Cl . A yields five constitutional isomers. B yields four constitutional isomers. C yields two constitutional isomers. D yields three constitutional isomers, two of which possess stereo-genic centres. E yields three constitutional isomers, only one of which possesses a stereo-genic centre. Identify the structures of Aโ€“E.

Questions: Compounds A and B are isomers having molecular formula C5H12. Heating A with Cl2 gives a single product of monohalogenation, whereas heating B under the same conditions forms three constitutional isomers. What are the structures of A and B?

Question: Using Mechanism 15.1 as a guide, write the mechanism for the reaction of CH4with Br2 to form CH3 Br and HBr. Classify each step as initiation, propagation, or termination.

Question: Draw all constitutional isomers formed when each alkene is treated with NBS + hฮฝ.

a.

b.

c.
See all solutions

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