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Chapter 12: PROBLEM 12.2 (page 458)

Question: What alkane is formed when each alkene is treated with H2 and a Pd catalyst?

a.

b.

c.

Short Answer

Expert verified

Answer

a.

b.

c.

Step by step solution

01

Hydrogenation of Alkenes

Symmetric addition of H2 to the double bond of alkene gives alkane as a product.

Palladium is used as a catalyst in the reaction; it assists in the breaking of π -bond and formation of σ-bond

02

Action of H2 and Pd on alkenes

The double bond is broken, and a hydrogen atom is added on either side of the C=C double bond.

a.

Cleavage of the double bond

b.

Cleavage of the double bond

c.

Cleavage of the double bond

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Most popular questions from this chapter

Question: Draw the products formed when A is treated with each reagent: (a) H2 Pd-C; (b) mCPBA; (c) PCC; (d) CrO3, H2SO4, H2O; (e) Sharpless reagent with (+)-DET.

Question: Sodium hypochlorite (NaOCl, the oxidant in household bleach) in aqueous CH3COOH is also touted as a “green” oxidizing agent. For example, oxidation of (CH3)2CHOH with NaOCl forms along with NaCl and H2O. (a) What advantages and/or disadvantages does this method have over oxidation with HCrO4––Amberlyst A-26 resin? (b) What advantages and/or disadvantages does this method have over oxidation with CrO3, H2SO4,H2O.

Question: Draw a stepwise mechanism for the following reaction.

Question: Epoxidation of the following allylic alcohol using the Sharpess reagent (-)-DET gives two epoxy alcohols in a ratio of 87:13.

  1. Assign structures to the major and minor product.
  2. What is the enantiomeric excess in this reaction?

Question: Draw all alkenes that react with one equivalent of H2 in the presence of a palladium catalyst to form each alkane. Consider constitutional isomers only

a.

b.

c.
See all solutions

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