Question

Question: Draw the products of each reaction

a.

b.

Short answer

Answer

a.

b.

Step-by-step solution

Reduction of sigma bonds with LiAlH4

LiAlH₄ is used for the reduction of alkyl halide or epoxide. It donates H^- ions which replaces the X^- ions in alkyl halide.

The reaction follows S_N2 mechanism; hence it completes in a single step only. In epoxides, the H^- ion attack on less substituted carbon.

Action of  LiAlH4

a. A hydrogen atom substitutes chlorine.

Reduction of alkyl halide

b. Hydrogen is substituted, and the C-O bond is broken.

Reduction of epoxide