Chapter 14: Q6P (page 527)
Question: Label the protons in each highlighted \({\bf{C}}{{\bf{H}}_{\bf{2}}}\) group as enantiotopic, diastereotopic, or homotopic.
a.
b.
c.
Short Answer
Enantiotopic
Neither
Diastereotopic
Chapter 14: Q6P (page 527)
Question: Label the protons in each highlighted \({\bf{C}}{{\bf{H}}_{\bf{2}}}\) group as enantiotopic, diastereotopic, or homotopic.
a.
b.
c.
All the tools & learning materials you need for study success - in one app.
Get started for freeQuestion. In the presence of a small amount of acid, a solution of acetaldehyde(CH3CHO) in methanol (CH3OH) was allowed to stand and a new compound L was formed. L has a molecular ion in its mass spectrum at 90 and IR absorptions at 2992 and 2941cm-1 . L shows three signals in its 13C-NMR at 19, 52, and 101 ppm. 1H-NMR spectrum of L is given below. What is the structure of L?
Which of the highlighted carbon atoms in each molecule absorbs farther downfield?
a.
b.
c.
d.
How many NMR signals does each compound give?
a.
b.
c.
d.
Question:Reaction of unknown A with HCl forms chlorohydrin B as the major product. A shows no absorptions in its IR spectrum at 1700 cm-1 or 3600-3200 cm-1 , and gives the following 1H NMR data: 1.4 (doublet, 3 H), 3.0 (quartet of doublets, 1 H), 3.5 (doublet, 1 H), 3.8 (singlet, 3 H), 6.9 (doublet, 2 H), and 7.2 (doublet, 2 H) ppm.
(a) Propose a structure for A, including stereochemistry.
(b) Explain why B is the major product in this reaction.
Question: Explain why the carbonyl carbon of an aldehyde or ketone absorbs farther downfield than the carbonyl carbon of an ester in a 13C NMR spectrum
What do you think about this solution?
We value your feedback to improve our textbook solutions.