Chapter 14: Q3P (page 527)
Question: How many \(^{\bf{1}}{\bf{H}}\) NMR signals does each compound show?
a.
b.
c.
d.
e.
f.
g.
h.
Short Answer
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Chapter 14: Q3P (page 527)
Question: How many \(^{\bf{1}}{\bf{H}}\) NMR signals does each compound show?
a.
b.
c.
d.
e.
f.
g.
h.
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Get started for freeQuestion: Identify the carbon atoms that give rise to the signals in the 13C NMR spectrum of each compound.
a. CH3CH2CH2CH2OH ; 13CNMR: 14, 19, 35, and 62 ppm
b. (CH3)2CHCHO ; 13C NMR: 16, 41, and 205 ppm
c. CH2=CHCHOHCH3 ; 13C NMR: 23, 69, 113, and 143 ppm
How many lines are observed in the 13C NMR spectrum of each compound?
a.
b.
c.
d.
The 1H NMR spectrum of CH3OH recorded on a 500 MHz NMR spectrometer consists of two signals, one due to the CH3 protons at 1715 Hz and one due to the OH proton at 1830 Hz, both measured downfield from TMS. (a) Calculate the chemical shift of each absorption. (b) Do the CH3 protons absorb upfield or downfield from the OH proton?
Draw all constitutional isomers of molecular formula C3H6Cl2.
a. How many signals does each isomer exhibit in its 1HNMR spectrum?
b.How many lines does each isomer exhibit in its 13CNMR spectrum?
c. When only the number of signals in both 1Hand 13C NMR spectroscopy is considered, is it possible to distinguish all of these constitutional isomers?
Question: Treatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm-1, and gives the following 1 H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 22.
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