Chapter 14: Q30P (page 527)
Which of the highlighted carbon atoms in each molecule absorbs farther downfield?
a.
b.
c.
d.
Short Answer
a.
b.
c.
d.
Chapter 14: Q30P (page 527)
Which of the highlighted carbon atoms in each molecule absorbs farther downfield?
a.
b.
c.
d.
a.
b.
c.
d.
All the tools & learning materials you need for study success - in one app.
Get started for freeFor each compound, first label each different type of proton and then rank the protons in order of increasing chemical shift.
a.
b.
c.
Question: Reaction of C6H5CH2CH2OH with CH3COCl affords compound W, which has molecular formula C10H12O2. W shows prominent IR absorptions at 3088โ2897, 1740, and 1606cm-1 . W exhibits the following signals in its 1 H NMR spectrum: 2.02 (singlet), 2.91 (triplet), 4.25 (triplet), and 7.20โ7.35 (multiplet) ppm. What is the structure of W? We will learn about this reaction in Chapter 22.
What splitting pattern is observed for each proton in the following compounds?
a.
b.
Question: Using a 300 MHz NMR instrument:
a. How many Hz downfield from TMS is a signal at 2.5 ppm?
b. If a signal comes at 1200 Hz downfield from TMS, at what ppm does it occur?
c. If two signals are separated by 2 ppm, how many Hz does this correspond to?
What do you think about this solution?
We value your feedback to improve our textbook solutions.