Chapter 14: Q,21558-14-75P (page 569)
Question: Explain why the 13C NMR spectrum of 3-methylbutan-2-ol shows five signals.
Short Answer
Answer
Since the replacement of each by X atoms forms two diastereomers, the CH3 groups are not equivalent to those attached to the third carbon.. Thus, every C in this compound is different, and there are five 13-C signals.