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Chapter 14: Q,21558-14-75P (page 569)

Question: Explain why the 13C NMR spectrum of 3-methylbutan-2-ol shows five signals.

Short Answer

Expert verified

Answer

Since the replacement of each by X atoms forms two diastereomers, the CH3 groups are not equivalent to those attached to the third carbon.. Thus, every C in this compound is different, and there are five 13-C signals.

Step by step solution

01

13C-NMR

The 13C-NMR splitting pattern reflects how many protons are directly attached to the carbon atom.The 13C-NMR helps to distinguish between CH1 ,CH2 ,CH3groups.

02

3-methylbutan-2-ol

3-methylbutan-2-ol

Since the replacement of each by X atoms forms two diastereomers, the CH3 groups are not equivalent to those attached to the third carbon.. Thus, every C in this compound is different, and there are five 13-C signals.

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