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Chapter 14: Q.21558-14-73P (page 569)

Question: The 1 H NMR spectrum of N,N-dimethylformamide shows three singlets at 2.9, 3.0, and 8.0 ppm. Explain why the two groups are not equivalent to each other, thus giving rise to two NMR signals.

Short Answer

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Answer

Step by step solution

01

 1H NMR

The number of signals in a PMR spectrum is equal to the number of kinds of protons present in the molecule. The splitting of the NMR signal is caused by spin-spin coupling

02

Non-equivalent proton in NMR

The structure for N,N-dimethylformamide places the two CH3 groups in different environments and different chemical shifts. One CH3 group is cis to the O atom, and one is cis to the H atom.

This gives rise to two different absorptions for the CH3 groups.

Representation of cis

It should be noted that spin-spin splitting is observed only between non-equivalent neighboring protons.

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