Chapter 14: Q.21558-14-49P (page 563)
Question: Rank the highlighted carbon atoms in each compound in order of increasing chemical shift.
a.
b.
Short Answer
Answer
a. Ca< Cb < Cc
b. Cc < Cb< Ca
Chapter 14: Q.21558-14-49P (page 563)
Question: Rank the highlighted carbon atoms in each compound in order of increasing chemical shift.
a.
b.
Answer
a. Ca< Cb < Cc
b. Cc < Cb< Ca
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Get started for freeQuestion: Treatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm-1, and gives the following 1 H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 22.
Question: How many 1H NMR signals does each natural product exhibit?
a.
b.
c.
d.
Draw all constitutional isomers of molecular formula \({{\bf{C}}_{\bf{3}}}{{\bf{H}}_{\bf{6}}}{\bf{C}}{{\bf{l}}_{\bf{2}}}\).
a. How many signals does each isomer exhibit in its \({}^{\bf{1}}{\bf{H}}\) NMR spectrum?
b. How many lines does each isomer exhibit in its \({}^{{\bf{13}}}{\bf{C}}\) NMR spectrum?
c. When only the number of signals in both \({}^{\bf{1}}{\bf{H}}\) and \({}^{{\bf{13}}}{\bf{C}}\) NMR spectroscopy is considered, is it possible to distinguish all of these constitutional isomers?
Identify A and B, isomers of molecular formula C3H4Cl2 , from the given 1HNMR data: Compound A exhibits signals at 1.75 (doublet, 3H,J = 6.9 Hz) and 5.89 (quartet, 1H, J = 6.9 Hz) ppm. Compound B exhibits signals at 4.16 (singlet, 2 H), 5.42 (doublet, 1H, J = 1.9 Hz), and 5.59 (doublet, 1H, J = 1.9 Hz) ppm.
Question: How many \(^{\bf{1}}{\bf{H}}\) NMR signals does each dimethylcyclopropane show?
a.
b.
c.
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