Chapter 14: Q.21558-14-30P. (page 558)
Which of the highlighted carbon atoms in each molecule absorbs farther downfield?
a.
b.
c.
d.
Short Answer
a.
b.
c.
d.
Chapter 14: Q.21558-14-30P. (page 558)
Which of the highlighted carbon atoms in each molecule absorbs farther downfield?
a.
b.
c.
d.
a.
b.
c.
d.
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Get started for freeQuestion. In the presence of a small amount of acid, a solution of acetaldehyde(CH3CHO) in methanol (CH3OH) was allowed to stand and a new compound L was formed. L has a molecular ion in its mass spectrum at 90 and IR absorptions at 2992 and 2941cm-1 . L shows three signals in its 13C-NMR at 19, 52, and 101 ppm. 1H-NMR spectrum of L is given below. What is the structure of L?
Question: Label the protons in each highlighted \({\bf{C}}{{\bf{H}}_{\bf{2}}}\) group as enantiotopic, diastereotopic, or homotopic.
a.
b.
c.
Question:Reaction of unknown A with HCl forms chlorohydrin B as the major product. A shows no absorptions in its IR spectrum at 1700 cm-1 or 3600-3200 cm-1 , and gives the following 1H NMR data: 1.4 (doublet, 3 H), 3.0 (quartet of doublets, 1 H), 3.5 (doublet, 1 H), 3.8 (singlet, 3 H), 6.9 (doublet, 2 H), and 7.2 (doublet, 2 H) ppm.
(a) Propose a structure for A, including stereochemistry.
(b) Explain why B is the major product in this reaction.
Question: Using a 300 MHz NMR instrument:
a. How many Hz downfield from TMS is a signal at 2.5 ppm?
b. If a signal comes at 1200 Hz downfield from TMS, at what ppm does it occur?
c. If two signals are separated by 2 ppm, how many Hz does this correspond to?
Sketch the NMR spectrum of CH3CH2Cl , giving the approximate location of each NMR signal.
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