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Chapter 14: Q.21558-14-19P. (page 551)

Draw a splitting diagram for Hb in trans-1,3-dichloropropene, given that Jab = 13.1 Hz and Jbc = 7.2 Hz.

Short Answer

Expert verified

Spin-spin coupling is the interaction of proton spins through the mediating bonding electrons. The bonding electron pairs its spin with the spin of the nearest proton.

Step by step solution

01

Spin-spin coupling

Spin-spin coupling is the interaction of proton spins through the mediating bonding electrons. The bonding electron pairs its spin with the spin of the nearest proton.

02

Coupling constant (J)

The distance between the peaks in a multiplet is called the coupling constant. The coupling constant is a measure of how strongly a nucleus is affected by the spin states of its neighbor. Its magnetic field is independent of applied field strength.

03

Drawing a splitting diagram for Hb.

Structure of trans-1, 3-dichloroprene

1 trans Ha proton splits the Hb into 1 + 1 = 2 peaks, so it will get a doublet. 2 Hc protons split Hb into 2 + 1 = 3 peaks, then a doublet of triplets is obtained. Therefore, the splitting diagram for Hb can be drawn as:

Splitting diagram for Hb

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Most popular questions from this chapter

Question: Using a 300 MHz NMR instrument:

a. How many Hz downfield from TMS is a signal at 2.5 ppm?

b. If a signal comes at 1200 Hz downfield from TMS, at what ppm does it occur?

c. If two signals are separated by 2 ppm, how many Hz does this correspond to?

Question:Propose a structure consistent with each set of spectral data:

a. C4H8Br2: IR peak at 3000–2850cm-1 ;

NMR (ppm):

1.87 (singlet, 6 H)

3.86 (singlet, 2 H)

b. C3H6Br2: IR peak at 3000–2850cm-1 ;

NMR (ppm):

2.4 (quintet)

3.5 (triplet)

c. C5H10O2: IR peak at 1740cm-1 ;

NMR (ppm):

1.15 (triplet, 3 H) 2.30 (quartet, 2 H)

1.25 (triplet, 3 H) 4.72 (quartet, 2 H)

d . C6H14O: IR peak at 3600-3200 cm-1 ;

NMR (ppm):

0.8 (triplet, 6 H) 1.5 (quartet, 4 H)

1.0 (singlet, 3 H) 1.6 (singlet, 1 H)

e. C6H14O: IR peak at 3000-2850cm-1 ;

NMR (ppm):

1.10 (doublet, relative area = 6)

3.60 (septet, relative area = 1)

f . C3H6O: IR peak at 1730cm-1 ;

NMR (ppm):

1.11 (triplet)

2.46 (multiplet)

9.79 (triplet)

Label each statement as True or False.

a. When a nucleus is strongly shielded, the effective field is larger than the applied field and the absorption shifts downfield.

b. When a nucleus is strongly shielded, the effective field is smaller than the applied field and the absorption is shifted upfield.

c. A nucleus that is strongly deshielded requires a lower field strength for resonance.

d. A nucleus that is strongly shielded absorbs at a larger δ value.

What splitting pattern is observed for each proton in the following compounds?

a.

b.

How many NMR signals would you expect for each compound?

a.

b.

c.

See all solutions

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