Chapter 14: Q.21558-14-17P. (page 549)

How many peaks are present in the NMR signal of each labelled proton?
a.
b.
c.
d.

Short Answer

Expert verified

a. 7 peaks

b. 3, 5, 12, and 6 peaks

c. 2 and 6 peaks

d. 4, 4, and 4 peaks

Step by step solution

NMR Spectra

NMR involves the interaction of radiowaves with magnetic nuclei. Only those nuclei which have non-zero values of spin exhibit magnetic property. The spin quantum number of nuclei is represented by I, which has 2I +1 degenerate magnetic levels.

Equation to find the number of peaks

If non-equivalent protons are present in the neighborhood of a given set of protons, then (n + 1) peaks will arise in the NMR spectrum.

If two sets of non-equivalent protons (a and b) are present, then the multiplicity is given by (n_a + 1)(n_b + 1) . But if the coupling constant of a and b protons are approximately the same, the rule reduces to (n_a + n_b + 1) .

To find the number of peaks present in the NMR signal of the labeled proton.

The condensed formula of a

6 equivalent hydrogen atoms split the labeled proton. So, the number of peaks is given by (6 + 1) = 7 peaks.

The condensed formula of b

The labeled proton H_a is split by 2 hydrogen atoms. So, the number of peaks due to H_a is given by (2 + 1) = 3 peaks. The proton H_c is split by 4 equivalent hydrogen atoms. So, the number of peaks due to H_c is given by (4 + 1) = 5 peaks.

The proton H_b is split by 2 sets of hydrogen atoms. So, the maximum number of peaks will be (3 + 1)(2 + 1) = 12 peaks. But the signal due to H_b will have a peak overlap as this is a flexible alkyl chain. And the number of peaks that will be likely visible is 3 + 3+ 2+ 1 = 6 peaks.

The condensed formula of c

The labeled proton H_a is split by 1 hydrogen atom. So, the number of peaks due to H_a is given by (1 + 1) = 2peaks. The proton H_b is split by 2 sets of hydrogen atoms. So, the number of peaks due to H_b will be (1 +1)(2 +1) = 6 peaks.