Question

Question: Rank the compounds in each group in order of increasing strength of intermolecular forces.

a.

b.

Short answer

Answer

a. The compounds can be arranged in the increasing strength of intermolecular forces as follows:

b.The arrangement of the compounds in the increasing order of strength of intermolecular forces is as follows:

Step-by-step solution

Intermolecular forces

Intermolecular forces are viewed as less powerful in comparison to intramolecular forces.

Hydrogen bonding is a particular intermolecular force that takes place because of the dipole-dipole interaction between the hydrogen atom and an electronegative atom.

The distance between the molecules influences the weak chemical forces, which are the Vander Waals forces. Molecules comprising permanent dipoles interact using specific interactions. These are termed the dipole-dipole interactions.

Increasing strength of intermolecular forces in the compounds of question

a.

The intermolecular forces can be arranged in the increasing order of strength as follows:

$Vanderwalls<Dipole-dipole<hydrogenbonding$

The interactions present in cyclopentamine include Vander Waals, dipole-dipole, and hydrogen bonding. The interactions present in chlorocyclopentane are Vander Waals and dipole-dipole interaction, whereas, in methylcyclopentane, it is Vander Waals force.

Hence, the molecules in the increasing order of intermolecular forces can be represented as follows:

The increasing strength of intermolecular forces in the compounds

Increasing strength of intermolecular forces in the compounds of question

b.

The interactions present in 2,3-dimethylbutene are Vander Waals forces. The interactions present in 2-Methyl propanoic acid are Vander Waals forces, hydrogen bonding, and dipole-dipole interaction.

The interactions present in 3-methyl 2-butanone are Vander Waals forces and dipole-dipole interaction.

The increasing strength of intermolecular forces in the compounds