Question

Question: Draw the products formed when benzoyl chloride is treated with each nucleophile: (a) ${\mathbf{H}}_{\mathbf{2}}\mathbf{O}$, pyridine; (b)${\mathbf{CH}}_{\mathbf{3}}{\mathbf{COO}}^{\mathbf{-}}$ ; (c)${\mathbf{NH}}_{\mathbf{3}}$ (excess); (d)${\left({\mathrm{CH}}_3\right)}_{\mathbf{2}}\mathbf{NH}$ (excess).

Short answer

Answer

a. Reaction of C₆H₅COCl with H₂O , pyridine

b. Reaction of C₆H₅COCl with CH₃COO^-

c. Reaction of C₆H₅COCl with NH₃ (excess)

d. Reaction of C₆H₅COCl with (CH₃)₂NH (excess).

Step-by-step solution

Step-by-Step Solution  Step 1: Nucleophile

An ion or molecule that donates a pair of electrons to form a new bond is known as a nucleophile.

A nucleophile is a compound that shares its lone pair with an atom other than a proton.

Reaction with nucleophile

a. Reaction of C₆H₅COCl with H₂O , pyridine

b. Reaction of C₆H₅COCl with CH₃COO^-

c. Reaction of C₆H₅COCl with NH₃ (excess)

c. Reaction of C₆H₅COCl with NH₃ (excess)