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Match the C13NMR data to the appropriate structure.

Spectrum [1]: signals at 14, 22, 27, 34, 181 ppm

Spectrum [2]: signals at 27, 39, 186 ppm

Spectrum [3]: signals at 22, 26, 43, 180 ppm


a.

b.

c.

Short Answer

Expert verified

Spectrum [1]: Structure B

Spectrum [2]: Structure A

Spectrum [3]: Structure C

Step by step solution

01

C13 NMR 

The compound displays a single line in the NMR spectra for each unique carbon environment; therefore, it is useful for determining the number of non-equivalent carbons.

02

Data and appropriate structure

The number of types of non-equivalent carbons:

A - three types of carbons

three types of carbons

B - five types of carbons

five types of carbons

C - four types of carbons

four types of carbons

Each non-equivalent carbon will have a different J value; therefore, the appropriate matches are:

  1. A contains three types of carbons, so it matches with spectrum [2].
  1. B contains five types of carbons, so it matches with spectrum [1].
  1. C contains four types of carbons, so it matches with spectrum [3].

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