Question

Question: Identify A–D in the following reactions.

a.

b.

c.

d.

Short answer

Answer

a.

b.

c.

d.

Step-by-step solution

Step-by-Step Solution Step 1: Carboxylic acids

The organic compounds comprising a carboxy group are called carboxylic acids.Examples of carboxylic acid are formic acid and butanoic acid.

Preparation of carboxylic acids

Carboxylic acids can be generated from various compounds in several ways.Alcohols can be transformed into carboxylic acid by the reagent ${\mathbf{K}}_{\mathbf{2}}{\mathbf{Cr}}_{\mathbf{2}}{\mathbf{O}}_{\mathbf{7}}$ in the presence of ${\mathbf{H}}_{\mathbf{2}}\mathbf{O}$ and ${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$ .

Predicting the reactant of the given reactions

a. The reactant of the given reaction is ${\mathrm{C}}_7{\mathrm{H}}_8\mathrm{O}$. The oxidation of ${\mathrm{C}}_7{\mathrm{H}}_8\mathrm{O}$ leads to the formation of ${\mathrm{C}}_7{\mathrm{H}}_6{\mathrm{O}}_2$.

The C-O bonds replace the C-H bonds of the primary alcohol. The reagent utilized in this conversion is ${\mathrm{Na}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$ in the presence of water and sulfuric acid. Hence, compound A is${\mathrm{C}}_7{\mathrm{H}}_8\mathrm{O}$ .

Reaction a

b. The reactant in the given reaction is${\mathrm{CH}}_3\mathrm{C}\equiv \mathrm{CH}$. And the reagents are ozone and water.

The internal alkyne is utilized to form two equivalents of acetic acid in the presence of ozone and water. Hence compound B is${\mathrm{CH}}_3\mathrm{C}\equiv \mathrm{CH}$.

Reaction b

c. The reactant in the given reaction is${\mathrm{C}}_6{\mathrm{N}}_4\left({\mathrm{NO}}_2\right){\mathrm{CH}}_3$ . Here, the methyl group converts into carboxylic acid in the presence of ${\mathrm{KMNO}}_4$. Hence, compound C is ${\mathrm{C}}_6{\mathrm{N}}_4\left({\mathrm{NO}}_2\right){\mathrm{CH}}_3$ , and its name is 4-nitrotoulene.

Reaction c

d. The reactant in the given reaction is ${\mathrm{CH}}_3\mathrm{CO}{\left({\mathrm{CH}}_2\right)}_4{\mathrm{CH}}_2\mathrm{OH}$. Here, a primary alcohol is converted into carboxylic acid in the presence of ${\mathrm{CrO}}_3$, water, and sulfuric acid. Hence, compound D is ${\mathrm{CH}}_3\mathrm{CO}{\left({\mathrm{CH}}_2\right)}_4{\mathrm{CH}}_2\mathrm{OH}$ .

Reaction d