Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Devise a synthesis of (E)-1-phenylhex-1-ene ( CH3CH2CH2CH2CH=CHPh) using hydrocarbons having ≤ 6 C’s and a Suzuki reaction as one of the steps.

Short Answer

Expert verified

Answer

Mechanism of (E)-1-phenylhex-1-ene synthesis

Step by step solution

01

Organic synthesis

Generally, the demands for natural products are higher than the amount produced by nature. Therefore, the compounds have to be synthesized from smaller available organic compounds.

Therefore, organic synthesis is the route for the conversion of available starting materials to complex target molecules through a series of synthetic steps.

Coupling reactions, oxidation, reduction are carried out under controlled reaction conditions to increase yield in organic synthesis.

02

Suzuki reaction

Synthesis of biaryl compounds from aryl halides in the presence of aryl boronic catalyst is called Suzuki coupling.

The reaction was carried out in the presence of a homogenous palladium catalyst at a high temperature in an organic solvent.

Now, developed Suzuki reactions can be done in an aqueous solution using a heterogeneous catalyst.

03

Synthesis of (E)-1-phenylhex-1-ene

Pentane nitrile is the starting material. It reacts with aryl boronic acid to form the intermediate, which reacts with bromobenzene to form (E)-1-phenylhex-1-ene.

Bromobenzene is synthesized from benzene by bromination reaction.

Mechanism of synthesis of (E)-1-phenylhex-1-ene

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The reaction of cyclohexene with iodo-benzene under Heck conditions forms E, a coupling product with the new phenyl group on the allylic carbon, but none of the “expected” coupling product F with the phenyl group bonded directly to the carbon–carbon double bond.

a. Draw a stepwise mechanism that illustrates how E is formed.

b. Step [2] in Mechanism 26.2 proceeds with syn addition of Pd and R' to the double bond.What does the formation of E suggest about the stereochemistry of the elimination reaction depicted in Step [3] of Mechanism 26.2?

Although diazomethane ( CH2N2) is often not a useful reagent for preparing cyclopropanes,other diazo compounds give good yields of more complex cyclopropanes. Draw a stepwisemechanism for the conversion of diazo compound A to B, an intermediate in the synthesis ofsirenin, the sperm attractant produced by the female gametes of the water mold Allomyces.

Metathesis reactions can be carried out with two different alkene substrates in one reaction mixture. Depending on the substitution pattern around the C=C, the reaction may lead to one major product or a mixture of many products. For each pair of alkene substrates, draw all metathesis products formed. (Disregard any starting materials that may also be present at equilibrium.) With reference to the three examples, discuss when alkene metathesis with two different alkenes is a synthetically useful reaction.

Draw the product formed from the ring-closing metathesis of each compound. Then, devisea synthesis of each metathesis starting material using any of the following compounds: CH2(CO2Et)2, alcohols with less than five carbons, and any needed organic and inorganicreagents.

a.

b.

What compound is needed to convert styrene to each product using a Heck reaction?

a.

b.

c.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free