Question

What product is formed when each alkene is treated with and Zn(Cu)?

a.

b.

c.

Short answer

Answer

a.

b.

c.

Step-by-step solution

Alkene

Compounds consisting of double-bonds are designated as alkenes. Alkenes can be categorized into monosubstituted, disubstituted, etc., based on the count of alkyl groups connected to the carbon atom.

Simmons–Smith reaction

Alkenes combine with diiodomethane and the zinc reagent Zn(Cu) to create non-halogenated cyclopropanes. This reaction does not require a free carbene.

Treatment of the given alkenes with CH2I2 and Zn(Cu)

a.The given alkene reacts with CH₂I₂ and Zn(Cu) to form a non-halogenated cyclopropane. The reaction of alkene a with CH₂I₂ and Zn(Cu) can be given as:

Reaction of alkene a with CH₂I₂ and Zn(Cu)

b. The double bond of cyclopentene converts to a single bond on the reaction with CH₂I₂ and Zn(Cu). The reaction of alkene b with CH₂I₂ and Zn(Cu) can be given as:

Reaction of alkene b with CH₂I₂ and Zn(Cu)

c. The given alkene combines with CH₂I₂ and Zn(Cu) to produce a product comprising cyclopropane. The reaction of alkene c with CH₂I₂and Zn(Cu) can be given as:

Reaction of alkene c with ${\mathrm{CH}}_2{\mathrm{I}}_2$and Zn(Cu)