Question

Question: Draw the product formed by treating each compound with excess CH₃I , followed by Ag₂O, and then heat.

a.

b.

c.

Short answer

Answer

a.

b.

c.

Step-by-step solution

Hoffmann elimination 

In Hofmann elimination, the base removes a proton from the less substituted and more accessible $\alpha$carbon atom, because of the bulky leaving group on the nearby alpha carbon.

The bulky leaving group is obtained as quaternary ammonium salt by the attack of the amine to the methyl iodide via S_N2 reaction.

Explanation

a. The reaction of the given amine is completed via the Hoffmann elimination process as:

Hoffmann elimination in compound a.

b.The given amine produces the product alkene via the Hoffmann elimination process as:

Hoffmann elimination in compound b.

c. The given amine produces the product alkene via the Hoffmann elimination process as:

Hoffmann elimination in compound c.