Question

Draw the organic products formed in each reaction.

a

b

c

d

e

f

g

h

i

j

Short answer

a

b

c

d

e

f

g

h

i

j

Step-by-step solution

Reactions of amines

Amines function as bases with compounds comprising acidic protons. They function as nucleophiles among compounds possessing electrophilic carbons.

Reduction of functional groups comprising nitrogen

Nitro groups can be transformed into primary amines in the presence of reagents like tin and HCl. Nitriles can be transformed into primary amines with the help of lithium aluminum hydride$\left(LiAl{H}_4\right)$ .

Predicting the products formed in each reaction

a

Ammonia functions as the nucleophile in this particular reaction. The reaction between 2-chloroethyl)cyclohexane and excess ammonia leads to the formation of 2-cyclohexylethanamine as the product.

Products formed in reaction a

b.The product obtained by the reaction of 1-chloro-2-methyl-propane and pthalimide in the presence of base leads to the formation of 2-methylpropan-1-amine. The reaction can be given as:

Products formed in reaction b

c.The nitro group gets reduced to an amino group in the presence of Sn and HCl in this particular reaction. The reaction can be given as:

Products formed in reaction c

d. The cyano group gets reduced to methylamine in this reaction. The reaction can be given as:

Products formed in reaction d

e. In this reaction, N-ethylcyclohexanecarboxamide is reduced to N-(cyclohexylmethyl)ethanamine. The reaction can be given as:

Products formed in reaction e

f. The given amine, 2-phenylethanamine reacts with benzoylbezoate to form N-phenylethylbenzamide. The reaction can be given as:

Products formed in reaction f

g. Pyrrolidine combines with nitrous acid to form N-nitrosoamine. The reaction can be given as:

Products formed in reaction g

h. Pyrrolidine reacts with benzaldehyde to form an imine. The imine undergoes reduction to form 1-benzylpyrrolidine. The reaction can be given as:

Products formed in reaction h

i. Piperidine reacts with cyclohexanone to form an imine. The reaction can be given as:

Products formed in reaction i

j. N-isopropylpropan-1-amine reacts with excess methyl iodide to form an alkene. The reaction can be given as:

Products formed in reaction j