Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question: Which molecules contain good leaving groups?

a.

b.

c.

d.

CH3-CH3

Short Answer

Expert verified

ANSWER:

a. This molecule possesses a good leaving group.

b. This molecule does not contain a good leaving group.

c. This molecule contains a good leaving group.

d. This molecule does not possess a good leaving group.

Step by step solution

01

Leaving group

Species that leave a particular molecule taking an electron pair are known as leaving groups. There are several leaving groups, and some of them include halides like Cl-andBr-and tosylate TsO-.

02

Identification of compound possessing good leaving groups

Good leaving groups are the ones that possess a weak base and whose conjugate acids have a low pKavalue.

a. Br- is a good leaving group as it is a weak base, and the conjugate acid of Br-, which is HBr, possesses a low pKavalue.

b.OH- is not a good leaving group as it is a strong base, and its conjugate acid has a very high pKavalue.

c.H2O is a good leaving group as it is a weak base, and the conjugate acid of H2O, which is H3O+, possesses a low pKavalue.

d. H-is not a good leaving group as it is a strong base, and its conjugate acid possesses a high pKavalue.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: As you will learn in Chapter 9, the epoxide is an ether with an oxygen atom in a three-membered ring. Epoxides can be made by intramolecular SN2 reactions of intermediates that contain a nucleophile and a leaving group on adjacent carbons, as shown.

Assume that each of the following starting materials can be converted to an epoxide by this reaction. Draw the product formed (including stereochemistry) from each starting material. Why might some of these reactions be more difficult than others in yielding nucleophilic substitution products?

a.

b.

c.

d.

Question: Give the structure corresponding to each name.

a. 3-chloro-2-methylhexane

b. 4-ethyl-5-iodo-2,2-dimethyloctane

c. cis-1,3-dichlorocyclopentane

d. 1,1,3-tribromocyclohexane

e. sec-butyl bromide

f. 6-ethyl-3-iodo-3,5-dimethylnonane

Question: Consider the following SN1 reaction.

  1. Draw a mechanism for this reaction using curved arrows.
  2. Draw an energy diagram. Label the axes, starting material, product Eaand โˆ†Hยฐ. Assume that the starting material and product are equal in energy.
  3. Draw the structure of any transition states.
  4. What is the rate equation for this reaction?
  5. What happens to the reaction rate in each of the following instances? [1] The leaving group is changed from I- to Cl-;[2] The solvent is changed from H2O to DMF; [3] The alkyl halide is changed from (CH3)2 C(I) CH2CH3 to (CH3) CHCH(I)CH3 ; [4] The concentration of H2O is increased by a factor of five; and [5] The concentrations of both the alkyl halide and H2O are increased by factor of five.

Question: What nucleophile is needed to convert to each product?

a.


b.


c.

d.

Question: Uridine monophosphate (UMP) is one of the four nucleotides that compose RNA, the nucleic acid that translates the genetic information of DNA into proteins needed by cells for proper function and development. A key step in the synthesis of UMP is the reaction of A with B to form C, which is then converted to UMP in one step. Draw a stepwise mechanism for this SN1 reaction.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free