Question

Question: (a) Label the carbon–carbon double bond in A as E or Z. (b) Draw the products (including stereoisomers) formed when A is treated with ${\mathit{H}}_{\mathbf{2}}\mathit{O}$ in the presence of ${\mathit{H}}_{\mathbf{2}}\mathit{S}{\mathit{O}}_{\mathbf{4}}$.

Short answer

Answer

(a) Z configuration

(b)

Step-by-step solution

Step 1:E or Z configuration

When the priority groups are on the same side of the double bond, it is called Z configuration, and when they are on different sides, it is called E configuration.

Formation of products for a and b

(a)

The given compound is depicted below:

Given compound

The configuration of the given compound is represented as follows:

Z configuration

(b)

The reaction of the given compound with water in the presence of sulfuric acid gives the stereoisomers of alcohol.

The reaction is shown below:

Products in b