Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question: Glucose is a simple sugar with five substituents bonded to a six-membered ring.

a. Using a chair representation, draw the most stable arrangement of these substituents on the six-membered ring.

b. Convert this representation into one that uses a hexagon with wedges and dashed wedges.

c. Draw a constitutional isomer of glucose.

d. Draw a stereoisomer that has an axial OH group on one carbon.

Short Answer

Expert verified

Answer

a.

Most stable chair form of glucose

b.

Wedged and dashed wedged structure of glucose

c.

Fructose, a constitutional isomer of glucose

d.

β-D-glucopyranose,a stereoisomer with OH on the axial position

Step by step solution

01

Numbering

The numbers are assigned to the atoms in the ring, starting from oxygen.

Numbered ring structure of glucose

02

Draw chair form and add the substituents

The chair form of the ring is drawn. The atoms at position 1 and position 4 are picked, and one of them is assigned up and the other down positions.

Each atom in the ring has two substituents: one at the axial position and the other at the equatorial position. The axial groups on the up carbon atoms are on the upper side and vice-versa. The remaining positions are the equatorial positions.

Glucose ring in chair form

Arbitrarily assign the groups on the axial and equatorial positions on each carbon. In glucose, the OH groups are present on the opposite sides of two consecutive carbons.

Hence, starting from position 2, the groups are alternatively assigned on up and down positions. In this structure, starting from position 2, the groups are assigned the up alternatively.

The remaining bonds are filled with hydrogen (H) atoms.

03

Wedges and dashed wedges representation

The groups on the upper side of the ring are represented with a wedge, and those on down the ring are represented with dashed wedges.

04

Solutions

a. The most stable arrangement of the substituents in the chair form of glucose is represented below.

Most stable chair form of glucose

b. The upper side groups are represented with a solid wedge, and the down groups are represented with a dashed wedge on the hexagonal ring of glucose.

Wedged and dashed wedged structure of ring structure of glucose

c. The constitutional isomer of glucose is fructose. Glucose and fructose have the same molecular formula but different connectivities. Glucose has an aldehyde group, while fructose has a ketone group.

Fructose

d. The stereoisomer of glucose with an OH group on the axial position on carbon one is β-D-glucopyranose.

β-D-glucopyranose

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Answer the following questions about compound A, which contains a -CH3group and OH group bonded to the carbon skeleton that consists of three six-membered rings in the conformation shown.

a. Are the -CH3and OH groups oriented cis or trans to each other?

b. Is a substituent on localid="1648626189057" Cathat is cis to the CH3 group located in the axial or equatorial position?

c. Is an equatorial Br at Cboriented cis or trans to the OH group?

d. Is the H atom on Cclocated cis or trans to the OH group?

e. Is a substituent on Cdthat is trans to the OH group located in the axial or equatorial position?

Question: Calculate the barrier to rotation for each bond highlighted in pink.

a.

b.

Question: Draw the structure corresponding to each IUPAC name.

a. 3-ethyl-2-methylhexane

b. sec-butylcyclopentane

c. 4-isopropyl-2,4,5-trimethylundecane

d. cyclobutylcycloheptane

e. 3-ethyl-1,1-dimethylcyclohexane

f. 4-butyl-1,1-diethylcyclooctane

g. 6-isopropyl-2,3-dimethyldodecane

h. 2,2,6,6,7-pentamethyloctane

i. cis-1-ethyl-3-methylcyclopentane

j. trans-1-tert-butyl-4-ethylcyclohexane

Question: Convert each of the following structures into its more stable chair form. One structure represents menthol and one represents isomenthol. Menthol, the more stable isomer, is used in lip balms and mouthwash. Which structure corresponds to menthol?

Question: Mineral oil, a mixture of high molecular weight alkanes, is sometimes used as a laxative. Why are individuals who use mineral oil for this purpose advised to avoid taking it at the same time they consume foods rich in fat-soluble vitamins such as vitamin A?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free