Chapter 9: Q2. (page 335)

Question: Give the IUPAC name for each compound.
a.
b.
c.

Short Answer

Expert verified

Answer

a.3,3-dimethyl-1-pentanol

b.cis-2-methylcyclohexanol

c. 5-ethyl-6-methyl-3-nonanol

Step by step solution

Step-by-Step Solution Step 1: IUPAC nomenclature

The IUPAC naming gives the identity of an organic compound.

The carbon atoms in alkyl groups having a count of one, two, three, and so on in the IUPAC nomenclature are known as methane, ethane, and propane, respectively. The OH functional group is given as the -ol identity.

Naming in the IUPAC nomenclature

The counting is started from the functional group if present. The substituents are assigned the lowest number. In the absence of any main functional group, the substitution of the groups are prioritized.

Explanation

a. The given compound’s IUPAC name is 3,3-dimethyl-1-pentanol. There are 5 carbon atoms. Therefore, the pentane comes for the long chain. The counting is started from the OH side.

b. The given compound’s IUPAC name is cis-2-methylcyclohexanol. There are 6 membered carbon rings. Therefore, the cyclohexane name comes for the ring. The counting is started from the OH side.

The cis is given for the two groups present on the same side of the plane.

c. The given compound’s IUPAC name is 5-ethyl-6-methyl-3-nonanol. There are 9 carbon atoms. Therefore, the nonane comes for the long chain. The counting is started from the OH side.