Question

Draw the product formed when the Lewis acid ${\mathbf{\text{(CH}}}_{\mathbf{\text{3}}}{\mathbf{\text{CH}}}_{\mathbf{\text{2}}}{\mathbf{\text{)}}}_{\mathbf{\text{3}}}{\mathbf{\text{C}}}^{\mathbf{\text{+}}}$reacts with each Lewis base:

role="math" localid="1649304251552" ${\mathbf{\text{(a)CH}}}_{\mathbf{\text{3}}}{\mathbf{\text{OH;(b)(CH}}}_{\mathbf{\text{3}}}{\mathbf{\text{)}}}_{\mathbf{\text{2}}}{\mathbf{\text{O;(c)(CH}}}_{\mathbf{\text{3}}}{\mathbf{\text{)}}}_{\mathbf{\text{2}}}\mathbf{\text{NH.}}$

Short answer

The combination of a Lewis acid with a Lewis base produces the product that is noted as a Lewis acid-base adduct.Several of the Lewis acid-base reactions come under the category of displacement reactions.

Step-by-step solution

Lewis acid-base reaction

The combination of a Lewis acid with a Lewis base produces the product that is noted as a Lewis acid-base adduct.Several of the Lewis acid-base reactions come under the category of displacement reactions.

Reaction of (CH3CH2)3C+ with given compounds

(a) The Lewis base ${\text{CH}}_{\text{3}}\text{OH}$provides the electron to the Lewis acid leading to the formation of a Lewis acid-base adduct as given below:

(b) The Lewis base ${\text{(CH}}_{\text{3}}{\text{)}}_{\text{2}}\text{O}$donates the electron to the Lewis acid leading to the formation of a Lewis acid-base adduct, as shown below:

(c) The Lewis base${\text{(CH}}_{\text{3}}{\text{)}}_{\text{2}}\text{NH}$contributes its electron to the Lewis acid leading to the formation of a Lewis acid-base adduct as mentioned below: