Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question. Which of the following compounds are capable of being resolved into enantiomers?

(a)N-ethyl-N-propylaniline

(b) 2-ethylpiperidine

(c) 1-ethylpiperidine

(d) 1,2,2-triethylaziridine
(e)

(f)

(g)

(h)

Short Answer

Expert verified

(a) Not resolvable due to presence of planarity in the molecule.

(b) Resolvable due to presence of asymmetric carbon.

(c) Not resolvable due to symmetric nature of a molecule.

(d) Resolvable but nitrogen inversion is slow.
(e)
Not resolvable due to symmetric nature of the molecule.
(f)
Resolvable due to presence of asymmetric nitrogen, unable to invert.

(g)
Not resolvable in conditions where the proton on nitrogen can exchange.
(h)
Resolvable due to presence of asymmetric nitrogen, unable to invert.

Step by step solution

01

Step-1. Explanation of part (a):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (a), N-ethyl-N-propylaniline has fixed geometry and is planar due to attachment of different substituents and due to which it has plane of symmetry and is not chiral, hence it cannot undergo resolution into enantiomers. Plane of symmetry exists as the plane containing whole molecule as molecule is planar.


Not resolvable

02

Step-2. Explanation of part (b):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (b), 2-ethylpiperidine has nitrogen atom which is chiral or optically active due to attachment of different substituents to it, hence it can undergo resolution into enantiomers. Chiral center has been marked with asterisk.


Resolvable

03

Step-3. Explanation of part (c):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (c), 1-ethylpiperidine has plane of symmetry in its structure and thus will not be optically active, hence it cannot undergo resolution into enantiomers.

|
Not resolvable

04

Step-4. Explanation of part (d):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (d), 1,2,2-triethylaziridine has chiral center due to attachment of different substituents to it due to which rotation of nitrogen atom is restricted, and hence it can undergo resolution into enantiomers. Chiral center is marked with an asterisk.|

Resolvable

05

Step-5. Explanation of part (e):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (e), the structure has plane of symmetry present in it passing and hence it cannot undergo resolution into enantiomers.


Not Resolvable

06

Step-6. Explanation of part (f):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (f), the structure has chiral center present in it due to attachment of different groups to the nitrogen center and due to which rotation of nitrogen atom is restricted, and hence it can undergo resolution into enantiomers.

07

Step-7. Explanation of part (g):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers

In part (g), the structure is not resolvable in conditions where the proton on nitrogen atom can exchange. If proton exchange occurs, it means the nitrogen atom can undergo flipping due to introduction of planarity in the molecule after proton exchange. Thus the molecule is not resolvable into enantiomers.


Not resolvable if proton exchange on nitrogen occurs

08

Step-8. Explanation of part (h):

Compounds which are optically active can be resolved into the enantiomers and compounds which have bulkier group attached to nitrogen which restricts flipping can also undergo resolution into enantiomers.

In part (h), the structure has asymmetric nitrogen atom (marked by a star in the structure) which is unable to invert and thus will show resolution into enantiomers. It has attachment of different substituents to it which rotation of nitrogen atom is restricted, and hence it can undergo resolution into enantiomers.


Resolvable

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question. Section 17-12 showed how nucleophilic aromatic substitution can give aryl amines if there is a strong electron-withdrawing group ortho or para to the site of substitution. Consider the following example.


(a) Propose a mechanism for this reaction.
(b) We usually think of fluoride ion as a poor leaving group. Explain why this reaction readily displaces fluoride as the leaving group.
(c) Explain why this reaction stops with the desired product, rather than reacting with another dinitrofluorobenzene.

Question. A chemist is summoned to an abandoned waste-disposal site to determine the contents of a leaking, corroded barrel. The barrel reeks of an overpowering fishy odor. The chemist dons a respirator to approach the barrel and collect a sample, which she takes to her laboratory for analysis.

The mass spectrum shows a molecular ion at m/z101, and the most abundant fragment is at m / z86. The IR spectrum shows no absorptions above 3000 cm-1, many absorptions between 2800 and 3000 cm-1, no absorptions between 1500 and 2800 cm-1, and a strong absorption at 1200 cm-1. The proton NMR spectrum shows a triplet
(J = 7 HZ ) at 2.4, with integrals of 17 spaces and 11 spaces, respectively.

  1. Show what structural information is implied by each spectrum, and propose a structure for the unknown toxic waste.
  2. Current EPA regulations restrict the disposal of liquid wastes because they tend to leak out of their containers. Propose an inexpensive method for converting this waste to a solid, relatively odorless form for reburial.
  3. Suggest how the chemist can remove the fishy smell from her clothing.

Question. The following spectra for A and B correspond to two structural isomers. The NMR singlet at1.16in spectrum A disappears when the sample is shaken with . The singlet at 0.6 ppm in the spectrum B disappears on shaking with . Propose structures for these isomers, and show how your structures correspond to the spectra. Show what cleavage is responsible for the base peak at 44 in the mass spectrum of A and the prominent peak at 58 in the mass spectrum of B.







Question. Using any necessary reagents, show how you can accomplish the following multistep synthesis.

Question. Pyrrole undergoes electrophilic aromatic substitution more readily than benzene, and mild reagents and conditions are sufficient. These reactions normally occur at the 2-position rather than the 3-position, as shown in the following example.



  1. Propose a mechanism for the acetylation of pyrrole just shown. You may begin with pyrrole and the acylium ion,. Be careful to draw all the resonance structures of this intermediate.
  2. Explain why pyrrole reacts more readily than benzene, and also why substitution occurs primarily at the 2-position rather than 3-position.
See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free