The \(\mathrm{S}_{\mathrm{N}} 2\) reaction that occurs between an alkyl halide
and a nucleophile is a very important process in organic chemistry. For this
reason, it is necessary to recognize the nucleophilicity of various reagents.
In the following pairs of compounds, indicate the more nucleophilic reagent.
Explain your reasoning.
(a) \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N}
\quad\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{P}\)
(b) \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N}
\quad\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{2} \mathrm{~N}^{-}\)
(c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{SNa} \quad \mathrm{CH}_{3}
\mathrm{CH}_{2} \mathrm{OK}\)
There is much detail in this chapter, but that is not usually a problem for
most students. Good nucleophiles can be distinguished from good bases, good
leaving groups can be identified, and so on. What is hard is to learn to
adjust reaction conditions (reagents, temperature, and solvent) so as to
achieve the desired selectivity to favor the product of just one of these four
reactions. That's hard in practice as well as in answering a question on an
exam or problem set. To a certain extent, we all have to learn to live with
this problem!