Chapter 17: Problem 45
An imide is a functional group similar to an acid anhydride. Instead of an
oxygen between two carbonyls, an imide has a nitrogen between two carbonyls.
Suggest a method for making the imide shown below starting with pentanedioic
acid and benzyl amine.
Short Answer
Expert verified
React pentanedioic acid with benzyl amine to form an amide, followed by cyclization to form the imide.
Step by step solution
01
- Understand the Structure of the Imide
The goal is to form an imide, which has a nitrogen atom between two carbonyl groups. For the imide shown in the exercise, the nitrogen atom is bonded to a cyclic structure, specifically a six-membered ring with a nitrogen and two carbonyl groups.
02
- Identify the Reactants
The reactants are pentanedioic acid (a dicarboxylic acid) and benzyl amine (an amine with a benzyl group). The pentanedioic acid has two carboxylic acid groups (-COOH), and the benzyl amine has an amine group (-NH2) attached to a benzyl group (a phenyl group attached to a -CH2-).
03
- Create a Cyclic Structure
To form a six-membered ring imide, the pentanedioic acid must react with the benzyl amine such that the amine group attacks one of the carboxylic acids, resulting in the formation of an amide. Concurrently, the second carboxylic acid group can undergo intramolecular cyclization, leading to cyclization and loss of water molecules.
04
- Formation of an Amide
The benzyl amine reacts with one of the carboxylic acid groups of pentanedioic acid. This forms an amide and releases a molecule of water (condensation reaction).
05
- Intramolecular Cyclization
The remaining carboxylic acid group undergoes dehydration to form an imide. The internal nucleophilic attack by the amide nitrogen onto the second carbonyl group closes the ring and another water molecule is removed.
06
- Verify Structural Formula
Confirm the resultant chemical structure to ensure it matches the given imide. You should now have a six-membered ring structure with a nitrogen atom between two carbonyl groups, attached to a benzyl group.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
organic chemistry
Organic chemistry focuses on compounds containing carbon atoms. It delves into the structure, properties, and reactions of organic molecules. In our exercise, we're working with pentanedioic acid, a dicarboxylic acid, and benzyl amine, an amine.
The foundation of organic chemistry involves understanding how different functional groups interact to form new compounds. Here, we combine an amine with a dicarboxylic acid to form an imide, a functional group characterized by a nitrogen atom bonded between two carbonyl groups. By understanding the basic principles of organic chemistry, you can easily grasp how provided reactants interact to form more complex structures.
The foundation of organic chemistry involves understanding how different functional groups interact to form new compounds. Here, we combine an amine with a dicarboxylic acid to form an imide, a functional group characterized by a nitrogen atom bonded between two carbonyl groups. By understanding the basic principles of organic chemistry, you can easily grasp how provided reactants interact to form more complex structures.
cyclization reactions
Cyclization reactions involve the formation of a ring structure within a molecule. In our context, pentanedioic acid reacts with benzyl amine forming a six-membered ring imide.
This process begins by reacting benzyl amine with one carboxylic group of pentanedioic acid to form an amide, releasing a water molecule (a typical condensation reaction). Next, the second carboxylic acid group reacts intramolecularly with the amide's nitrogen, leading to the formation of a cyclic imide. Here, another water molecule is released. Thus, cyclization involves both the formation of a new ring structure and the elimination of smaller molecules.
This process begins by reacting benzyl amine with one carboxylic group of pentanedioic acid to form an amide, releasing a water molecule (a typical condensation reaction). Next, the second carboxylic acid group reacts intramolecularly with the amide's nitrogen, leading to the formation of a cyclic imide. Here, another water molecule is released. Thus, cyclization involves both the formation of a new ring structure and the elimination of smaller molecules.
functional groups
Functional groups are specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. In this exercise, we deal with various functional groups - carboxylic acids (-COOH), amine (-NH2), and carbonyl groups (C=O) - and transition to an imide group.
The transformation involves multiple steps where the functional groups interact:
The transformation involves multiple steps where the functional groups interact:
- The carboxylic acid group reacts with the amine to form an amide.
- An intramolecular reaction between the amide and the remaining carboxylic acid group forms the imide.
amide formation
Amide formation is a crucial reaction in organic chemistry, often involved in forming more complex compounds like imides. It's typically a reaction between an amine and a carboxylic acid.
In our exercise, benzyl amine reacts with pentanedioic acid:
In our exercise, benzyl amine reacts with pentanedioic acid:
- The amine group (-NH2) of benzyl amine attacks the carbonyl carbon of one carboxylic acid group, forming an amide bond and releasing water, in a condensation reaction.
- This newly formed amide can further react in subsequent cyclization to form the target imide structure.