Chapter 4: Problem 73
Investigate the thermodynamic feasibility of the following propagation steps for opening the rings of cycloalkanes with \(\mathrm{n}=2-6 \mathrm{by}\) a free-radical mechanism. (1) \(\left(\mathrm{CH}_{2}\right)_{\mathrm{n}}+\mathrm{Br}^{-} \rightarrow \mathrm{BrCH}_{2}\left(\mathrm{CH}_{2}+\mathrm{n}-2 \mathrm{CH}_{2}\right.\) (2) \(\mathrm{BrCH}_{2}\left(\mathrm{CH}_{2}+\mathrm{n}-2 \mathrm{CH}_{2}+\mathrm{Br}_{2} \rightarrow\left(\mathrm{CH}_{2}\right)_{\mathrm{n}-2}\left(\mathrm{CH}_{2} \mathrm{Br}\right)_{2}+\mathrm{Br}^{-}\right.\) Use 83 kcal for the bond-dissociation energy of a normal C-C bond and \(68 \mathrm{kcal}\) for the bond-dissociation energy of a C-Br bond. (An easy way to solve a problem of this type is to first calculate AH of each step for cyclohexane where there is no strain, and then make suitable corrections for the strain which is present for small values of n.) Refer to the following table for your answer. Table 1. Total Strain of Cycloalkanes $$ \begin{array}{|c|c|c|} \hline \begin{array}{c} \text { Cycloalkane } \\ \left(\mathrm{CH}_{2}\right)_{\mathrm{n}} \end{array} & \mathrm{n} & \begin{array}{c} \text { Total strain } \\ (\mathrm{kcal} / \text { moles }) \end{array} \\ \hline \text { ethylene } & 2 & 22.4 \\ \hline \text { cyclopropane } & 3 & 27.6 \\ \hline \text { cyclobutane } & 4 & 26.4 \\ \hline \text { cyclopentane } & 5 & 6.5 \\ \hline \text { cyclohexane } & 6 & 0.0 \\ \hline \end{array} $$
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