Chapter 23: Problem 602
Outline a synthesis of cumene from cheap, readily available hydrocarbons. Then synthesize phenol from cumene.
Short Answer
Expert verified
To synthesize cumene from cheap, readily available hydrocarbons, we start with benzene and propylene and perform the Friedel-Crafts alkylation reaction in the presence of a Lewis acid catalyst, aluminum chloride (AlCl3). This forms cumene. Then, we synthesize phenol from cumene by first converting cumene to cumene hydroperoxide through oxidation using molecular oxygen, and then performing an acid-catalyzed cleavage using sulfuric acid, yielding phenol and acetone.
Step by step solution
01
Formation of Cumene from Benzene and Propylene
In the first step, we perform the Friedel-Crafts alkylation reaction to obtain cumene by combining benzene and propylene in the presence of a Lewis acid catalyst such as aluminum chloride (AlCl3).
Benzene (\(C_6H_6\)) + Propylene (\(C_3H_6\)) + AlCl3 → Cumene (\(C_9H_{12}\)) + HCl + AlCl3
This reaction represents the synthesis of cumene by Friedel-Crafts alkylation, in which the alkyl group of propylene is attached to the benzene ring. The Lewis acid catalyst, AlCl3, helps generate carbocation from propylene that attacks the benzene ring. The chloride ion (Cl-) reacts with the hydrogen in the benzene's ring and forms HCl.
02
Oxidation of Cumene to Cumene Hydroperoxide
To obtain phenol from cumene, we need to convert cumene into cumene hydroperoxide. The oxidation of cumene is performed by bubbling air (O2) through the solution of cumene.
Cumene (\(C_9H_{12}\)) + O2 → Cumene Hydroperoxide (\(C_9H_{12}O_2\))
During this reaction, molecular oxygen is added across the benzylic C-H bond of cumene, and cumene hydroperoxide is formed. This step is a radical reaction and requires a radical initiator like benzoyl peroxide.
03
Acid-Catalyzed Cleavage of Cumene Hydroperoxide
Now, we perform the acid-catalyzed cleavage of cumene hydroperoxide to obtain phenol and acetone. The reaction takes place in the presence of a strong acid, such as sulfuric acid (H2SO4).
Cumene Hydroperoxide (\(C_9H_{12}O_2\)) + H2SO4 → Phenol (\(C_6H_5OH\)) + Acetone (\(CH_3COCH_3\)) + H2SO4
Under acidic conditions, cumene hydroperoxide rearranges to form phenol and acetone products. This step is an important industrial process since both phenol and acetone are valuable chemicals in the chemical industry.
In summary, we have successfully outlined the synthesis of cumene from cheap, readily available hydrocarbons (benzene and propylene) through Friedel-Crafts alkylation. We then synthesized phenol from cumene by forming cumene hydroperoxide through oxidation, followed by an acid-catalyzed cleavage to yield phenol and acetone products.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Friedel-Crafts Alkylation
Friedel-Crafts Alkylation is a crucial reaction in organic chemistry used to form carbon-carbon bonds. This versatile method involves introducing an alkyl or acyl group onto an aromatic ring, typically benzene. In our synthesis of cumene, we employ the Friedel-Crafts alkylation to combine benzene with propylene. This reaction is facilitated by a Lewis acid catalyst, such as aluminum chloride (AlCl3).
Here's how it works:
Here's how it works:
- The Lewis acid catalyst aids in generating a carbocation from propylene, making it a strong electrophile.
- This carbocation then attacks the electron-rich benzene ring, leading to the formation of cumene.
- As a result, the benzene ring gains an alkyl group from propylene, forming cumene.
Oxidation Reactions
Oxidation reactions play a pivotal role in converting substances into more oxidized forms. In the transformation of cumene to phenol, oxidation reactions are employed to form cumene hydroperoxide. This involves bubbling air (O2) through cumene.
The process:
The process:
- Molecular oxygen is introduced to attack the benzylic C-H bond in cumene through a radical mechanism.
- A radical initiator, such as benzoyl peroxide, can be used to jumpstart the reaction.
- The result is the formation of cumene hydroperoxide, a crucial intermediate for the next step.
Acid-Catalyzed Reactions
Acid-catalyzed reactions are vital in organic chemistry, serving as mechanisms to rearrange or break down compounds. In our synthesis of phenol, the acid-catalyzed reaction involves breaking down cumene hydroperoxide.
Here's what happens:
Here's what happens:
- The presence of a strong acid, like sulfuric acid (H2SO4), catalyzes the cleavage of cumene hydroperoxide.
- This results in the production of phenol and acetone, both valuable chemical products.
- The reaction showcases how acids can act as catalysts, providing a pathway for otherwise slow or unlikely transformations.
Industrial Chemical Processes
Industrial chemical processes are processes designed for mass production of chemical substances, supporting various sectors. The synthesis of phenol from cumene is an excellent example of such a process, demonstrating efficiency and utility in industrial settings.
Key aspects include:
Key aspects include:
- Utilizing readily available hydrocarbons like benzene and propylene reduces costs and ensures a sustainable supply chain.
- The sequence leveraging Friedel-Crafts alkylation, oxidation, and acid-catalyzed reactions allows for the systematic production of phenol, an important commodity chemical.
- Phenol is used extensively in the production of plastics, resins, and pharmaceuticals, making its efficient synthesis crucial to meet industrial demand.