Chapter 22: Problem 539
Novocaine, a local anesthetic, is a compound of formula \(\mathrm{C}_{13} \mathrm{H}_{20} \mathrm{O}_{2} \mathrm{~N}_{2}\). It is insoluble in water and dilute \(\mathrm{NaOH}\), but soluble in dilute HC1. Upon treatment with \(\mathrm{NaNO}_{2}\) and \(\mathrm{HCl}\) and then with \(\beta\) -naphthol, a highly colored solid is formed. When Novocaine is boiled with aqueous \(\mathrm{NaOH}\), it slowly dissolves. The alkaline solution is shaken with ether and the layers are separated. Acidification of the aqueous layer causes the precipitation of a white solid A; continued addition of acid causes \(A\) to redissolve. Upon isolation \(A\) is found to have a melting point of \(185-6^{\circ}\) and the formula \(\mathrm{C}_{7} \mathrm{H}_{7} \mathrm{O}_{2} \mathrm{~N}\). Evaporation of the ether layer leaves a liquid \(\mathrm{B}\) of formula \(\mathrm{C}_{6} \mathrm{H}_{15} \mathrm{ON}\). B dissolves in water to give a solution that turns litmus blue. Treatment of \(B\) with acetic anhydride gives C, \(\mathrm{C}_{8} \mathrm{H}_{17} \mathrm{O}_{2} \mathrm{~N}\), which is insoluble in water and dilute base, but soluble in dilute HCl. \(\mathrm{B}\) is found to be identical with the compound formed by the action of diethylamine on ethylene oxide. (a) What is the structure of Novocaine? (b) Outline all steps in a complete synthesis of Novocaine from toluene and readily available aliphatic and inorganic reagents. $$ \begin{array}{|l|l|l|} \hline {\text { CARBOXYLIC ACIDS }} \\ \hline \text { Name } & \text { Formula } & \begin{array}{c} \text { M.p. } \\ { }^{\circ} \mathrm{C} \end{array} \\ \hline \text { o-Nitrobenzoic } & \circ-\mathrm{O}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 147 \\ \hline \text { m-Nitrobenzoic } & \mathrm{m}-\mathrm{O}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 141 \\ \hline \text { p-Nitrobenzoic } & \mathrm{p}-\mathrm{O}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 242 \\ \hline \text { Phthalic } & \mathrm{o}-\mathrm{C}_{6} \mathrm{H}_{4}(\mathrm{COOH})_{2} & 231 \\ \hline \text { Isophthalic } & \mathrm{m}-\mathrm{C}_{6} \mathrm{H}_{4}(\mathrm{COOH})_{2} & 348 \\ \hline \text { Terephthalic } & \mathrm{p}-\mathrm{C}_{6} \mathrm{H}_{4}(\mathrm{COOH})_{2} & 300 \text { sub1. } \\ \hline \text { Salicylic } & \mathrm{o}-\mathrm{HOC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 159 \\ \hline \text { p-Hydroxybenzoic } & \mathrm{p}-\mathrm{HOC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 213 \\ \hline \text { Anthranilic } & \mathrm{o}-\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 146 \\ \hline \text { m-Aminobenzoic } & \mathrm{m}-\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 179 \\ \hline \text { p-Aminobenzoic } & \mathrm{p}-\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 187 \\ \hline \text { o-Methoxybenzoic } & \mathrm{o}-\mathrm{CH}_{3} \mathrm{OC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 101 \\ \hline \text { m-Methoxybenzoic } & \mathrm{m}-\mathrm{CH}_{3} \mathrm{OC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 110 \\ \hline \text { p-Methoxybenzoic(Anisic) } & \mathrm{p}-\mathrm{CH}_{3} \mathrm{OC}_{6} \mathrm{H}_{4} \mathrm{COOH} & 184 \\ \hline \end{array} $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.