Chapter 16: Problem 342
When allowed to react with aqueous HBr, 3 -buten \(-2-\circ 1\) \(\left(\mathrm{CH}_{3} \mathrm{CHOHCH}=\mathrm{CH}_{2}\right)\) yields not only 3 -bromo-1-butene \(\left(\mathrm{CH}_{3} \mathrm{CHBrCH}=\mathrm{CH}_{2}\right)\) but also 1 -bromo-2-butene \(\left(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{Br}\right)\) (a) How do you account for these results? (b) Predict the product of the reaction between \(\mathrm{HBr}\) and 2 -buten-1-o1 \(\left(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{OH}\right)\).
Short Answer
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