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\(1,3,5,7-\) Cyclooctatetraene, \(\mathrm{C}_{8} \mathrm{H}_{8}\), has a heat of combustion of \(1095 \mathrm{kcal} ;\) it rapidly decolorizes cold aqueous \(\mathrm{KMnO}_{4}\), and reacts with \(\mathrm{Br}_{2} / \mathrm{CCl}_{4}\), to yield \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{Br}_{8}\). (a) How should its structure be represented? (b) Upon what theoretical grounds might one have predicted its structure and properties? (c) Treatment of cyclooctatetraene with potassium metal has been found to yield a stable compound \(2 \mathrm{~K}^{+} \mathrm{C}_{8} \mathrm{H}_{8}{ }^{--}\) Of what significance is the formation of this salt? (d) Using models, suggest a possible shape (or shapes) for cyclooctatetraene. What shape would you predict for the \(\mathrm{C}_{8} \mathrm{H}_{8}^{--}\) anion?

Short Answer

Expert verified
Cyclooctatetraene has a conjugated, planar structure with alternating carbon-carbon double bonds. Its structure and reactivity can be predicted based on its molecular formula and reactions with electrophiles. The formation of a stable anion when treated with potassium metal suggests strong electron delocalization within the molecule. Both the neutral molecule and anion adopt flat, eight-membered ring structures with alternating carbon-carbon single and double bonds, while the anion may experience slight curvature due to repulsion between negatively charged carbon atoms.

Step by step solution

01

(a) Structure Representation of Cyclooctatetraene

To determine the structure of cyclooctatetraene, we can use the fact that it reacts with \(\mathrm{Br}_{2}\) in \(\mathrm{CCl}_{4}\) to yield \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{Br}_{8}\). This indicates that all double bonds are present on the cyclooctatetraene. Using this information, we can represent the structure as follows: ``` H H H H \ / \ / \ / C - C - C - C - C - C - / \ / \ / \ H H H H ``` Each carbon atom is bonded to two other carbon atoms and one hydrogen atom, resulting in a total of 8 carbon atoms and 8 hydrogen atoms in the molecule.
02

(b) Theoretical Predictions of Structure and Properties

Using the molecular formula \(\mathrm{C}_{8} \mathrm{H}_{8}\), we can determine that Cyclooctatetraene has 2 fewer hydrogen atoms than an alkane with 8 carbon atoms. Thus, it must have 4 fewer single bonds, which means it contains 4 double carbon-carbon bonds. From this, we can deduce that the structure of Cyclooctatetraene will likely resemble that of a conjugated diene. This indicates that the molecule should be planar and stabilized by resonance, which will give it a higher heat of combustion than expected for a non-conjugated system. Additionally, since Cyclooctatetraene contains double bonds, it should be susceptible to reactions with electrophiles like \(\mathrm{KMnO}_{4}\) and \(\mathrm{Br}_{2}\), providing further support for the structure reported in part (a).
03

(c) Significance of Salt Formation with Potassium Metal

The formation of a stable compound \(2\mathrm{K}^{+}\mathrm{C}_{8}\mathrm{H}_{8}^{--}\) when Cyclooctatetraene is treated with potassium metal indicates that the molecule has the ability to accept electrons and form an anionic species. This suggests that the molecule's 4 double bonds are readily accessible for electron donation, which hints at strong electron delocalization throughout the structure. The presence of a stable anionic salt also indicates that the structure of Cyclooctatetraene is likely planar and stabilized by resonance.
04

(d) Possible Shapes of Cyclooctatetraene and Its Anion

As discussed earlier, the structure of Cyclooctatetraene suggests a planar, conjugated system with alternating double bonds. Therefore, its possible shape can be envisioned as a flat, eight-membered ring with adjacent carbon atoms connected by double and single bonds. The \(\mathrm{C}_{8} \mathrm{H}_{8}^{--}\) anion, formed by accepting electrons from the potassium metal, is likely to adopt a similar structure to Cyclooctatetraene. However, the anion might experience slight curvature in the structure, as the extra electrons will cause some repulsion between the negatively charged carbon atoms. This would result in a less planar, somewhat puckered shape for the anion, still maintaining the alternating pattern of single and double carbon-carbon bonds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alkene Reactions
Alkenes, organic compounds with carbon-carbon double bonds, play a significant role in chemical reactions due to their electrophilic nature. In the context of cyclooctatetraene, the molecule's reaction with potassium permanganate (KMnO4) and bromine (Br2) illustrates typical alkene behavior.

For instance, the addition of Br2 to alkenes is a classic example of a halogenation reaction, where the bromine molecule becomes attached across the double bond. Such reactions are useful not only for adding functional groups to a molecule but also for inferring the presence of double bonds. Cyclooctatetraene's rapid decolorization of KMnO4 demonstrates its ability to undergo oxidation reactions, which is characteristic of alkenes. This provides a valuable clue about the location of double bonds within the molecule.
Conjugated Diene
A conjugated diene is a system where double bonds are separated by a single bond, allowing for greater electron delocalization across the pi bonds. Cyclooctatetraene has four double bonds, suggesting it should have the properties of a conjugated diene.

This conjugation confers additional stability to the molecule, known as conjugation energy. The extra stability arises due to the overlapping p orbitals, which allows electrons to delocalize over several adjacent atoms. This structure inherently impacts the molecule's reactivity and can lead to unique reactions, such as the Diels-Alder reaction.

In the case of cyclooctatetraene, however, despite initial assumptions of having a planar, conjugated structure, the molecule fails to exhibit typical conjugated diene stability—this is due to the ring strain present in an eight-membered ring that prohibits effective conjugation.
Resonance Stabilization
Resonance stabilization is a concept used to describe the delocalization of electrons in molecular structures with conjugated systems. Molecules with resonance stabilization generally have lower energies and greater stability than those without.

The formation of the stable ion 2 K+C8H82− when potassium reacts with cyclooctatetraene suggests some degree of delocalization and resonance stabilization. Potassium donates electrons to cyclooctatetraene, resulting in a dianion. In many conjugated systems, the charge would be delocalized over the molecule, but cyclooctatetraene's unique structure – which is not planar due to angle strain – limits this stabilization.

Nevertheless, the formation of the stable dianion hints at the unusual molecular orbitals of cyclooctatetraene, which allow for some degree of electron delocalization despite the molecule's non-planarity.

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Most popular questions from this chapter

For which of the following might you expect aromaticity (geometry permitting)? (a) The annulenes containing up to 20 carbons. (Annulenes are monocyclic compounds of the general formula \([-\mathrm{CH}=\mathrm{CH}-]_{\mathrm{n}}\). (b) The monocyclic polyenes \(\mathrm{C}_{9} \mathrm{H}_{10} \mathrm{C}_{9} \mathrm{H}_{9}^{+}, \mathrm{C}_{9} \mathrm{H}_{9}{ }^{-}\).

When benzene is treated with chlorine under the influence of ultraviolet light, a solid material of \(\mathrm{m}\). wt. 291 is formed. Quantitative analysis gives an empirical formula of \(\mathrm{CHC} 1 .\) (a) What is the molecular formula of the product? (b) What is a possible structural formula? (c) What kind of reaction has taken place? (d) Is the product aromatic? (e) Actually, the product can be isolated into six isomeric compounds, one of which is used as an insecticide (Gammexane or Lindane). How do these isomers differ from each other? (f) Are more than six isomers possible?

For a time the prism formula VI, proposed in 1869 by Albert Ladenburg of Germany, was considered as a possible structure for benzene, on the grounds that it would yield one monosubstitution product and three isomeric disubstitution products. (a) Draw Ladenburg structures of three possible isomeric dibromobenzenes. (b) On the basis of the Korner method of absolute orientation, label each Ladenburg structure in (a) as ortho, meta, or para. (c) Can the Ladenburg formula actually pass the test of isomer number? (Derivatives of Ladenburg "benzene," called prismanes, have actually been made.)

You have three bottles containing the three isomeric dibromobenzenes; they have the melting points \(+87^{\circ},+6^{\circ}\), and \(-7^{\circ} .\) By a great deal of work, you prepare six dibromonitrobenzenes \(\left(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{Br}_{2} \mathrm{NO}_{2}\right)\) and find that, of the six, one is related to (derived from or convertible into) the dibromobenzene of m.p. \(+87^{\circ}\), two to the isomer of m.p. \(+6^{\circ}\), and three to the isomer of m.p. \(-7^{\circ}\). Label each bottle with the correct name of ortho, meta, or' para. (This work was actually carried out by Wilhelm Körner, of the University of Milan, and was the first example of the Korner method of absolute orientation.)

Draw structures for each of the following: (a) m-Bromonitrobenzene (e) 2,4 -Dibromomesitylene (b) o-Ethyltoluene (f) Pheny 1 cyclohexane (c) \(p\) -Xylene (g) Biphenyl (d) 3-Nitrobenzene (h) Benzyl cyanide

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