Chapter 7: Problem 12
If the equilibrium constant for the reaction, \(2 X Y \rightleftharpoons X_{2}+Y_{2}\) is 81 what is the value of equilibrium constant for the reaction $$ X Y \rightleftharpoons \frac{1}{2} X_{2}+\frac{1}{2} Y_{2} $$ (a) 81 (b) 9 (c) 6561 (d) \(40.5\)
Short Answer
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Key Concepts
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