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The difference of water molecules in gypsum and plaster of Paris is (a) \(\frac{5}{2}\) (b) 2 (c) \(\frac{1}{2}\) (d) \(1 \frac{1}{2}\)

Short Answer

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The difference of water molecules in gypsum and plaster of Paris is 1.5.

Step by step solution

01

Identify the Formulas

Determine the chemical formulas for gypsum and plaster of Paris. Gypsum is calcium sulfate dihydrate, with the formula CaSO4·2H2O, and plaster of Paris is calcium sulfate hemihydrate, with the formula CaSO4·0.5H2O.
02

Calculate the Difference in Water Molecules

Find the difference in the number of water molecules between the two compounds. Gypsum has 2 water molecules, and plaster of Paris has 0.5 water molecules. The difference is 2 - 0.5 = 1.5 water molecules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gypsum and Plaster of Paris
Gypsum and Plaster of Paris are two substances that have been used for centuries in building, art, and industry. Gypsum, naturally occurring as a mineral, is commonly found in layered sedimentary deposits. It's composed of calcium sulfate dihydrate, making it particularly useful for making plaster.

Plaster of Paris, on the other hand, derives its name from a large deposit of gypsum located in Paris. It is a quick-setting gypsum plaster consisting of a fine white powder, which hardens when moistened and allowed to dry. This material is used for casting and construction.

Both gypsum and Plaster of Paris have significant historical, cultural, and practical relevance. They're used in restoration works, orthopedics for making casts, in art for sculptures, and in construction for creating supportive walls and ornaments, illustrating their versatility.
Chemical Formula of Gypsum
The chemical composition of a substance defines its properties and applications. Gypsum, known scientifically as calcium sulfate dihydrate, has the chemical formula \( CaSO4\cdot2H2O \). This indicates that each molecule of gypsum contains one calcium (Ca) atom, one sulfur (S) atom, four oxygen (O) atoms, and is bonded to two water (H2O) molecules.

The presence of water in its structure makes gypsum soft and malleable, which is why it's a preferred material for various construction and artistic applications. It can be ground into a fine powder, mixed with water, and then molded into desired shapes. As it sets, it reverts to the hard, yet brittle, form of gypsum, making it an excellent plaster material.
Chemical Formula of Plaster of Paris
Plaster of Paris, also known as calcium sulfate hemihydrate, carries the chemical formula \( CaSO4\cdot0.5H2O \). This formula reveals that in Plaster of Paris, for every molecule of calcium sulfate, there is half a molecule of water, making it a 'hemihydrate' – 'hemi' meaning half and 'hydrate' relating to water.

The reduced water content compared to gypsum makes Plaster of Paris much quicker to set, a property exploited in its use. When mixed with water, it re-forms into gypsum but in a much more solid and dense form after drying. This quick-drying property makes it ideal for casts as it can conform quickly to the shape of a limb or for molds in art and architecture because it captures details precisely and sets rapidly.

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Most popular questions from this chapter

When \(\mathrm{BeCl}_{2}\) is hydrolysed, white fumes of gas are given out. The intensity of fumes intensifies when a rod dipped in moist ammonia is brought near the mouth of the test tube. The gas which comes out during hydrolysis is (a) \(\mathrm{Cl}_{2}\) (b) \(\mathrm{HCl}\) (c) \(\mathrm{NH}_{4} \mathrm{OH}\) (d) \(\mathrm{NH}_{4} \mathrm{Cl}\)

The normal oxide contains ion, peroxide contains ion and superoxide contains ion. (a) \(\mathrm{O}^{2-}, \mathrm{O}_{2}^{2-}, \mathrm{O}_{2}^{-}\) (b) \(\mathrm{O}^{2-}, \mathrm{O}_{2}^{-}, \mathrm{O}_{2}^{2-}\) (c) \(\mathrm{O}^{-}, \mathrm{O}^{2-}, \mathrm{O}^{3-}\) (d) \(\mathrm{O}_{0}^{-} \mathrm{O}^{2-}, \mathrm{O}_{2}^{2-}\)

Superoxides of alkali metals act as oxidising agents while normal oxides are basic in nature. The oxide which is paramagnetic in nature due to presence of unpaired electron is (a) \(\mathrm{Na}_{2} \mathrm{O}_{2}\) (b) \(\mathrm{KO}_{2}\) (c) \(\mathrm{Na}_{2} \mathrm{O}\) (d) \(\mathrm{K}_{2} \mathrm{O}_{2}\)

When kept open in air, the crystals of washing soda lose 9 molecules of water to form a monohydrate. \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O} \frac{\text { exposed }}{\text { to air }}>\mathrm{Na}_{2} \mathrm{CO}_{3} \mathrm{H}_{2} \mathrm{O}+9 \mathrm{H}_{2} \mathrm{O}\) This process is called (a) efflorescence (b) deliquescence (c) dehydration (d) hydration.

Which among the following is kinetically inert towards water? (a) \(\mathrm{Na}\) (b) Be (c) \(\mathrm{Ca}\) (d) \(\mathbf{K}\)

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