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On reaction with dihydrogen the alkali metals (a) form hydrides which are ionic solids with high melting points (b) form hydrides which are molecular solids with low melting points (c) form hydrides which are ionic solids with low melting points (d) form hydrides which are non-stoichiometric.

Short Answer

Expert verified
(a) Alkali metals react with dihydrogen to form hydrides which are ionic solids with high melting points.

Step by step solution

01

Understanding the Reactivity of Alkali Metals with Dihydrogen

Alkali metals are highly reactive and readily react with dihydrogen to form metal hydrides. These metals are located in the first group of the periodic table and include elements like lithium, sodium, potassium, etc.
02

Characterizing Alkali Metal Hydrides

Alkali metal hydrides are ionic compounds. The metal donates its outer electron to hydrogen, forming a cation (M+) and an anion (H-). The resulting compound is an ionic solid due to this electron transfer.
03

Assessing the Melting Points of Alkali Metal Hydrides

Since alkali metal hydrides are ionic compounds, they have strong electrostatic forces of attraction between the cations and anions. These strong ionic bonds give alkali metal hydrides high melting points.
04

Determining the Correct Option

Based on the properties of ionic bonding and the reactivity of alkali metals with dihydrogen, it can be concluded that the hydrides formed are ionic solids with high melting points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reactivity of Alkali Metals
When considering the reactivity of alkali metals, it is essential to look at their placement within the periodic table. Occupying Group 1, these metals, including lithium, sodium, potassium, etc., display a characteristic eagerness to lose their single valence electron and form cations. This eagerness, also known as reactivity, increases as we move down the group from lithium to cesium.

The high reactivity is partly due to the low ionization energy required to remove the outermost electron. Given this propensity to react, when alkali metals come into contact with dihydrogen, they rapidly form metal hydrides. These compounds are notable for their high melting points, which can be attributed to the strength of the ionic bonds formed between the respective metal cations and hydride anions. By understanding this fundamental behavior, learners can predict and explain the reactivity patterns of alkali metals.
Ionic Compounds
Diving deeper into the nature of ionic compounds, such as those formed by the reaction of alkali metals with dihydrogen, we find that their distinct properties are all tied to the ionic bonds that hold them together. An ionic bond is the electrostatic force of attraction between positively charged ions (cations) and negatively charged ions (anions).

In the context of metal hydrides, the alkali metal atom donates an electron to become a cation, while the hydrogen atom accepts an electron to become an anion (H-). This exchange results in a crystalline lattice structure that is characteristically solid with a high melting point due to the substantial forces holding the ions in place. Strength and rigidity define these compounds, making them significantly different from molecular solids that rely on weaker forces and generally possess low melting points. Understanding the structure and bonding of ionic compounds aids in predicting properties such as conductivity, melting and boiling points, and solubility.

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Most popular questions from this chapter

The difference of water molecules in gypsum and plaster of Paris is (a) \(\frac{5}{2}\) (b) 2 (c) \(\frac{1}{2}\) (d) \(1 \frac{1}{2}\)

An oxide of allkaline earth metals \((X)\) reacts with \(\mathrm{C}\) and \(\mathrm{Cl}_{2}\) to give a compound \(Y . Y\) is found in polymeric chain structure and is electron deficient molecule. The compound \(Y\) is (a) \(\mathrm{BeO}\) (b) \(\mathrm{BeCl}_{2}\) (c) \(\mathrm{Be}(\mathrm{OH})_{2}\) (d) \(\mathrm{BeCO}_{3}\)

A solution of a compound \(X\) in dilute \(\mathrm{HCl}\) on treatment with a solution of \(\mathrm{BaCl}_{2}\) gives a white precipitate of a compound \(Y\) which is insoluble in coac. \(\mathrm{HNO}_{3}\) and conc. \(\mathrm{HCl}\). Compound \(X\) imparts golden yellow colour to the flame. yellow colour) What are compounds \(X\) and \(Y ?\) (a) \(X\) is \(\mathrm{MgCl}_{2}\) and \(Y\) is \(\mathrm{BaSO}_{4}\)(b) \(X\) is \(\mathrm{CaCl}_{2}\) and \(Y\) is \(\mathrm{BaSO}_{4}\) (c) \(X\) is \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) and \(Y\) is \(\mathrm{BaSO}_{4}\) (d) \(X\) is \(\mathrm{MgSO}_{4}\) and \(Y\) is \(\mathrm{BaSO}_{4}\)

When sodium reacts with excess of oxygen, the oxidation number of oxygen changes from (a) 0 to-1 (b) 0 to \(-2\) (c) \(-1\) to \(-2\) (d) No change.

Which of the following statements is not true about alkali metals? (a) All alkali metals form oxo salts such as carbonates, sulphates and nitrates. (b) The basic character of oxides increases down the group. (c) Carbonates and sulphates of lithium are stable and their stability decreases down the group. (d) Solubility of carbonates and sulphates increases down the group.

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