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The correct order of relative acidity is: (a) \(\mathrm{HClO}>\mathrm{HClO}_{2}>\mathrm{HClO}_{3}>\mathrm{HClO}_{4}\) (b) \(\mathrm{HClO}_{4}>\mathrm{HClO}_{3}>\mathrm{HClO}_{2}>\mathrm{HClO}\) (c) \(\mathrm{HClO}>\mathrm{HClO}_{4}>\mathrm{HClO}_{2}>\mathrm{HClO}_{3}\) (d) \(\mathrm{HClO}_{3}>\mathrm{HClO}_{2}>\mathrm{HClO}_{4}>\mathrm{HClO}\)

Short Answer

Expert verified
The correct order of relative acidity is (b) \(\mathrm{HClO}_{4} > \mathrm{HClO}_{3} > \mathrm{HClO}_{2} > \mathrm{HClO}\).

Step by step solution

01

Understanding the Compounds

The compounds in the given options are oxyacids of chlorine: \(\mathrm{HClO}\), \(\mathrm{HClO}_{2}\), \(\mathrm{HClO}_{3}\), and \(\mathrm{HClO}_{4}\). Their acidity depends on the number of oxygen atoms bonded to chlorine. Generally, more oxygens mean a stronger acid.
02

Determine the Effect of Oxygen on Acidity

For oxyacids, the acidity increases with the number of oxygen atoms. This is because more oxygen atoms increase the electron-withdrawing ability, thereby stabilizing the conjugate base after the acid donates a proton (\(\mathrm{H}^+\)). The order is \(\mathrm{HClO}_{4}\) > \(\mathrm{HClO}_{3}\) > \(\mathrm{HClO}_{2}\) > \(\mathrm{HClO}\).
03

Match the Correct Order to the Options

Checking the options, we see that only option (b) presents the order \(\mathrm{HClO}_{4}\) > \(\mathrm{HClO}_{3}\) > \(\mathrm{HClO}_{2}\) > \(\mathrm{HClO}\), which is consistent with the trend determined from step 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxyacids of Chlorine
Oxyacids of chlorine are a group of acids where chlorine is bonded to one or more oxygen atoms. These acids include hypochlorous acid (HClO), chlorous acid (HClO₂), chloric acid (HClO₃), and perchloric acid (HClO₄). The structure of these acids greatly influences their acidity levels. A primary concept to understand is that the more oxygen atoms are attached to the chlorine, the stronger the acid. This essentially creates a better electron-withdrawing environment, making it easier for the acid to donate its proton ( H}^+ ). More oxygen atoms mean that the electron density can spread out better once the acid loses a proton, increasing the stability of the resulting anion, or conjugate base. So, the key takeaway here is: the number of oxygen atoms plays a crucial role in determining the strength of these oxyacids.
Electron-Withdrawing Effect
Electron-withdrawing effect is a term used to describe how atoms or groups of atoms can pull electron density away from other parts of a molecule. This effect can significantly influence the acidity of a compound, particularly in the context of oxyacids of chlorine. In these oxyacids, oxygen atoms exhibit a strong electron-withdrawing effect. This means they decrease the electron density around the hydrogen atom in the O-H bond. With less electron density, the H atom can more easily dissociate as a proton ( H}^+ ), thereby increasing the acidity. Effects on Acidity:
  • More oxygen atoms increase the electron-withdrawing effect.
  • The stronger the electron-withdrawing effect, the more acidic the oxyacid.
  • This effect leads to a greater stabilization of the conjugate base.
Understanding this effect helps explain why perchloric acid ( HClO₄ ) is stronger than hypochlorous acid ( HClO ). It highlights the pivotal role of electron-withdrawing groups in influencing acid strength.
Conjugate Base Stability
The stability of a conjugate base is a critical factor in determining the acidity of an acid. When an acid donates a proton ( H}^+ ), it forms its conjugate base. The more stable this conjugate base, the stronger the acid. In oxyacids of chlorine, conjugate base stability is increased when there is more effective dispersal of the negative charge that remains after proton donation. Oxygen atoms are key players here because they can distribute this charge over a larger area of the molecule. Stability Factors:
  • The more oxygen atoms, the better the charge distribution.
  • Better charge distribution stabilizes the conjugate base.
  • Increased stability of the conjugate base correlates with increased acid strength.
This phenomenon explains why, as the number of oxygen atoms in an oxyacid increases, its acidity typically increases as well. Perchloric acid ( HClO₄ ) offers the optimal distribution for charge stability, making it the strongest among these acids.

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Most popular questions from this chapter

For the reaction: \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}), \Delta \mathrm{H}=-93.6 \mathrm{~kJ}\) \(\mathrm{mol}^{-1}\), the concentration of \(\mathrm{H}_{2}\) at equilibrium can be increased by: (1) Lowering the temperature (2) Increasing the volume of the system (3) Adding \(\mathrm{N}_{2}\) at constant volume (4) Adding \(\mathrm{H}_{2}\) at constant volume (a) (ii) and (iv) are correct (b) Only (ii) is correct (c) (i), (ii) and (iii) are correct (d) (iii) and (iv) are correct

For the reaction, \(\mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}\), the rate constants for the forward and backward reactions are found to be \(4.2 \times 10^{-2}\) and \(3.36 \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\) respectively. What is the equilibrium constant for the reaction: (a) \(11.5\) (b) \(12.5\) (c) \(8.0\) (d) \(6.0\)

For the hypothetical reactions, the equilibrium constant \((\mathrm{K})\) values are given: \(\mathrm{A} \rightleftharpoons \mathrm{B} \mathrm{K}_{1}=2\) \(\mathrm{B} \rightleftharpoons \mathrm{C} \mathrm{K}_{2}^{1}=4\) \(\mathrm{C} \rightleftharpoons \mathrm{D} \mathrm{K}_{3}^{2}=3\) The equilibrium constant \((\mathrm{K})\) for the reaction: \(\mathrm{A} \rightleftharpoons \mathrm{D}\) is (a) 3 (b) 6 (c) 12 (d) 24

At constant temperature, the equilibrium constant \(\left(\mathrm{K}_{\mathrm{p}}\right.\) ) for the decomposition reaction: \(\mathrm{N}_{2} \mathrm{O}_{4} \rightleftharpoons 2 \mathrm{NO}_{2}\) is expressed by \(\mathrm{K}_{\mathrm{p}}=\left(4 \mathrm{x}^{2} \mathrm{P}\right) /\left(1-\mathrm{x}^{2}\right)\), where \(\mathrm{P}=\) pressure, \(\mathrm{x}=\) extent of decomposition. Which one of the following statements is true? (a) \(\mathrm{K}_{\mathrm{p}}\) increases with increase of \(\mathrm{P}\) (b) \(\mathrm{K}_{\mathrm{p}}\) increases with increase of \(\mathrm{x}\) (c) \(K_{p}\) increases with decrease of \(x\) (d) \(K_{p}\) remains constant with change in \(P\) and \(x\)

One mole of HI was heated in a sealed tube at \(440^{\circ} \mathrm{C}\) till the equilibrium was reached. HI was found to be \(22 \%\) decomposed. The equilibrium constant for dissociation reaction, \(2 \mathrm{HI} \rightleftharpoons \mathrm{H}_{2}+\mathrm{I}_{2}\) is: (a) \(1.99\) (b) \(0.282\) (c) \(0.01988\) (d) \(0.0796\)

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