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Which of the following is a tribasic acid? (a) \(\mathrm{H}_{3} \mathrm{PO}_{4}\) (b) \(\mathrm{H}_{3} \mathrm{PO}_{3}\) (c) \(\mathrm{H}_{3} \mathrm{PO}_{2}\) (d) \(\mathrm{HPO}_{3}\)

Short Answer

Expert verified
(a) \( \mathrm{H}_{3} \mathrm{PO}_{4} \) is the tribasic acid.

Step by step solution

01

Identify Tribasic Acid

A tribasic acid is an acid that can donate three hydrogen ions (protons), hence contains three replaceable hydrogen ions in its molecular structure.
02

Examine the Chemical Formula

Look at the chemical formulas given:- (a) \(\mathrm{H}_{3} \mathrm{PO}_{4}\) has three hydrogen atoms bonded to oxygen that can be ionized.- (b) \(\mathrm{H}_{3} \mathrm{PO}_{3}\) has two hydrogen atoms bonded directly to oxygens that can be ionized and one hydrogen atom is directly bonded to phosphorus, not replaceable.- (c) \(\mathrm{H}_{3} \mathrm{PO}_{2}\) has one hydrogen bonded to oxygen and two hydrogens bonded to phosphorus atoms, so only one ionizable hydrogen.- (d) \(\mathrm{HPO}_{3}\) is hypophosphorous acid, only having one replaceable hydrogen.
03

Determine the Correct Choice

Since \(\mathrm{H}_{3} \mathrm{PO}_{4}\) is the only option with three ionizable hydrogen atoms, it is the tribasic acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid Hydrogen Ionization
Understanding the concept of acid hydrogen ionization is crucial to identifying a tribasic acid. When an acid ionizes, it releases hydrogen ions, often referred to as protons. Tribasic acids are those special acids capable of releasing three hydrogen ions upon complete ionization. These hydrogen ions make an acid contribute to forming three hydronium ions, significantly affecting the acid's behavior in solution.

The ability to release multiple hydrogen ions means that tribasic acids have three stages of ionization. Each hydrogen ion is released in a stepwise manner, with each subsequent ionization step generally being less favorable than the last. This tiered ionization process affects many properties of the acid, such as its strength and interactions in various chemical reactions.
  • Stepwise ionization involves different ionization constants for each hydrogen ion.
  • This impacts their strength and application in solutions.
Phosphoric Acid
Phosphoric acid, \(\mathrm{H}_{3} \mathrm{PO}_{4}\), serves as a prime example of a tribasic acid. As noted in its chemical formula, phosphoric acid contains three replaceable hydrogen atoms. This structure allows it to undergo complete ionization, releasing three distinct hydrogen ions in a stepwise manner.

In the molecular makeup of phosphoric acid, these hydrogen atoms are bonded to oxygen atoms. This setup is essential because only hydrogen atoms attached to electronegative elements like oxygen can dissociate as protons. This dissociation enables phosphoric acid to form three hydronium ions when fully ionized, explaining why it acts as a tribasic acid.

Phosphoric acid's ability to release three protons is both a practical and theoretical consideration. It is used in various applications such as fertilizers and food additives, where its ionization property is beneficial. Its chemical behavior is also a focus in academic studies and industrial applications.
Comparative Acid Strength
When comparing the strength of acids, it is important to understand how the number of ionizable hydrogen atoms influences their acid strength. The concept of comparative acid strength allows us to analyze why some acids are stronger than others. Although having three ionizable hydrogen atoms does not automatically make an acid strong, like in the case of tribasic acids, it often affects how the acid behaves in solutions.

The strength of an acid is typically measured by its ability to donate protons in solution, which is related to its dissociation constant (\(Ka\)). However, each ionizable hydrogen in a tribasic acid like phosphoric acid has a distinct \(Ka\) value, decreasing progressively with each step. This characteristic means that the first hydrogen ion is the easiest to ionize, making that step the strongest and most complete.
  • Each acid has specific dissociation constants related to each hydrogen ionization.
  • Lower \(Ka\) values indicate decreasing strength in subsequent ionizations.
This decrease explains why tribasic acids are not collectively stronger than monoprotic acids in their initial ionization, but can have more sustained reactions over multiple ionizations.

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Most popular questions from this chapter

For the reaction: \(\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\) at a given temperature, the equilibrium amount of \(\mathrm{CO}_{2}(\mathrm{~g})\) can be increased by (a) Adding a suitable catalyst (b) Adding an inert gas (c) Decreasing the volume of the container (d) Increasing the amount of \(\mathrm{CO}(\mathrm{g})\)

One mole of a compound AB reacts with one mole of compound CD according to the equation: \(\mathrm{AB}+\mathrm{CD} \rightarrow \mathrm{AD}+\mathrm{CB}\) When equilibrium had been established it was found that \(3 / 4\) mole each of reactant \(\mathrm{AB}\) and \(\mathrm{CD}\) has been converted to AD and CB. There is no change in volume. The equilibrium constant of the reaction is? (a) 9 (b) \(\frac{1}{9}\) (c) \(9 / 16\) (d) \(16 / 9\)

The ratio of \(\mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}\) for the reaction: \(\mathrm{CO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{CO}_{2}(\mathrm{~g})\) is (a) 1 (b) RT (c) \((\mathrm{RT})^{1 / 2}\) (d) \((\mathrm{RT})^{-1 / 2}\)

If an inert gas is added in the reaction: \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\) at constant volume, then its equi- librium (a) Remains unaffected (b) Favours the backward reaction (c) Favours the forward reaction (d) Increases the dissociation of reactants

For the reaction \(\mathrm{C}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g})\), the partial pressures of \(\mathrm{CO}_{2}\) and \(\mathrm{CO}\) are 4 and \(8 \mathrm{~atm}\) respectively. The value of \(K_{p}\) for this reaction is: (a) \(14 \mathrm{~atm}\) (b) \(16 \mathrm{~atm}\) (c) \(18 \mathrm{~atm}\) (d) \(12 \mathrm{~atm}\)

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