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In \(\mathrm{X}-\mathrm{Hi}-\mathrm{Y}\), where both \(\mathrm{X}\) and \(\mathrm{Y}\) are electronegative elements: (a) Electron density of \(\mathrm{X}\) will increase and the eletron density on \(\mathrm{H}\) will decrease (b) On both species electron density will increase (c) On both species electron density will decrease (d) On \(\mathrm{X}\) the electron density will decrease and on \(\mathrm{H}\) it will increases

Short Answer

Expert verified
(a) Electron density of \( \mathrm{X} \) will increase and the electron density on \( \mathrm{H} \) will decrease.

Step by step solution

01

Understanding Electron Density

Electron density refers to the probability of finding an electron in a particular location around a nucleus. It is typically higher around electronegative atoms because they have a stronger tendency to attract electrons.
02

Identifying Electropositive and Electronegative Elements

In a molecule like \( \mathrm{X}-\mathrm{Hi}-\mathrm{Y} \), if both \( \mathrm{X} \) and \( \mathrm{Y} \) are electronegative elements, they will attract electron density towards themselves more than hydrogen \( \mathrm{H} \), which is less electronegative.
03

Analyzing Effects on Electron Density

When \( \mathrm{X} \) and \( \mathrm{Y} \) are electronegative, the electron density is more likely to be drawn away from hydrogen \( \mathrm{H} \) towards \( \mathrm{X} \) and \( \mathrm{Y} \). This increases electron density on \( \mathrm{X} \) and decreases it on \( \mathrm{H} \).
04

Choosing the Correct Answer

Based on the analysis that \( \mathrm{X} \) attracts electrons more than \( \mathrm{H} \), option (a) is correct. The electron density on \( \mathrm{X} \) will increase, while on \( \mathrm{H} \) it will decrease.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity
Electronegativity is a measure of how strongly atoms attract electrons when forming a chemical bond. Some atoms, like fluorine, are very electronegative and pull electrons towards them strongly. Others, like cesium, have low electronegativity and are not good at attracting electrons.
When you consider a molecule of the form \( \mathrm{X}-\mathrm{Hi}-\mathrm{Y} \), where both \( \mathrm{X} \) and \( \mathrm{Y} \) are electronegative, they will pull on the electrons more than hydrogen \( \mathrm{H} \). This difference in electronegativity determines where electrons are most likely to be found in the molecule. The greater the difference in electronegativity between atoms, the more polarized the electron distribution will be in the bond.
Electron Density
Electron density is a concept used to describe where electrons are located around an atom or molecule. In simple terms, it's a way of showing where electrons are likely to be in a compound.
Electronegative atoms increase electron density because they pull electrons towards them. In \( \mathrm{X}-\mathrm{Hi}-\mathrm{Y} \), both \( \mathrm{X} \) and \( \mathrm{Y} \) are more electronegative than hydrogen \( \mathrm{H} \). This means that the electron density around \( \mathrm{H} \) will decrease, as it is drawn towards the more electronegative elements. Therefore, the concept of electron density helps us visualize the distribution of electrons and understand how molecules will behave in chemical reactions.
  • Higher electronegativity = higher electron density
  • Lower electronegativity = lower electron density
Molecular Structure
Molecular structure refers to the three-dimensional arrangement of atoms within a molecule. It's like the architectural blueprint of the molecule that influences everything from chemical reactivity to physical properties.
For a molecule like \( \mathrm{X}-\mathrm{Hi}-\mathrm{Y} \), the positions of \( \mathrm{X} \), \( \mathrm{Hi} \), and \( \mathrm{Y} \) affect how the molecule will interact with other molecules. The electronegativity of \( \mathrm{X} \) and \( \mathrm{Y} \) pulls electron density away from \( \mathrm{Hi} \), causing shifts in the molecular structure which could affect molecular angles, bond lengths, and the overall shape of the molecule.
This structure is important because it can influence the chemical behavior and the physical attributes of the molecule, like how it might act under different temperatures or when mixed with other chemicals.
Covalent Bonds
Covalent bonds form when two atoms share electrons. These bonds are crucial for holding atoms together within a molecule. The way in which electrons are shared depends on the relative electronegativity of the participating atoms.
In \( \mathrm{X}-\mathrm{Hi}-\mathrm{Y} \), the covalent bonds are influenced by the fact that \( \mathrm{X} \) and \( \mathrm{Y} \) are more electronegative than \( \mathrm{H} \). This means the shared electrons will spend more time closer to the \( \mathrm{X} \) and \( \mathrm{Y} \) atoms, making these bonds polar. Therefore, covalent bonds between atoms of different electronegativities are not equal in sharing electrons, leading to partial charges on the atoms, which affects how the molecule interacts with other molecules and environments.
  • Covalent bonds can be polar or non-polar
  • Electronegativity differences determine the bond's polarity

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Most popular questions from this chapter

The bond order in \(\mathrm{NO}\) is \(2.5\) while that in \(\mathrm{NO}^{+}\) is 3 . Which of the following statements is true for these two species? (a) bond length in \(\mathrm{NO}^{+}\) is greater than in \(\mathrm{NO}\) (b) bond length in \(\mathrm{NO}\) is greater than in \(\mathrm{NO}^{+}\) (c) bond length in \(\mathrm{NO}^{+}\) is equal than in \(\mathrm{NO}\) (d) bond length is unpredictable

Bond angle in water is: (a) \(90^{\circ}\) (b) \(104.5^{\circ}\) (c) \(109.5^{\circ}\) (d) \(120^{\circ}\)

The correct order of hybridization of the central atom in the following species \(\mathrm{NH}_{3}, \mathrm{PtCl}_{4}^{-2}, \mathrm{PCl}_{5}\) and \(\mathrm{BCl}_{3}\) is: (a) \(\mathrm{dsp}^{2}, \mathrm{sp}^{3} \mathrm{~d}, \mathrm{sp}^{2}\) and \(\mathrm{sp}^{3}\) (b) \(\mathrm{sp}^{3}, \mathrm{dsp}^{2}, \mathrm{sp}^{3} \mathrm{~d}, \mathrm{sp}^{2}\) (c) \(\mathrm{dsp}^{2}, \mathrm{sp}^{2}, \mathrm{sp}^{3}, \mathrm{sp}^{3} \mathrm{~d}\) (d) \(\mathrm{dsp}^{2}, \mathrm{sp}^{3}, \mathrm{sp}^{2}, \mathrm{sp}^{3} \mathrm{~d}\)

In which of the following molecules/ions all the bonds are unequal? (a) \(\mathrm{SF}_{4}\) (b) \(\mathrm{SiF}_{4}\) (c) \(\mathrm{XeF}_{4}\) (d) \(\mathrm{BF}_{4}\)

Amongst \(\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S}, \mathrm{H}_{2} \mathrm{Se}\) and \(\mathrm{H}_{2}\) Te the one with the highest boiling point is: (a) \(\mathrm{H}_{2} \mathrm{O}\) because of hydrogen bonding (b) \(\mathrm{H}_{2}\) Te because of higher molecular weight (c) \(\mathrm{H}_{2} \mathrm{~S}\) because of hydrogen bonding (d) \(\mathrm{H}_{2}\) Se because of lower molecular weight.

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