Chapter 2: Problem 68
Which of the following sets of quantum numbers is correct for an electron in 4 f orbital? (a) \(\mathrm{n}=4, l=3, \mathrm{~m}=+4, \mathrm{~s}=+\frac{1}{2}\) (b) \(\mathrm{n}=4, l=4, \mathrm{~m}=-4, \mathrm{~s}=-\frac{1}{2}\) (c) \(\mathrm{n}=4, l=3, \mathrm{~m}=+1, \mathrm{~s}=+\frac{1}{2}\) (d) \(\mathrm{n}=3, l=2, \mathrm{~m}=-2, \mathrm{~s}=+\frac{1}{2}\)
Short Answer
Step by step solution
Understanding Quantum Numbers
Examining 4f Orbital Quantum Numbers
Evaluating Option (a)
Evaluating Option (b)
Evaluating Option (c)
Evaluating Option (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Principal Quantum Number
- Values of \( n \) can be 1, 2, 3, and so on.
- Higher \( n \) values correspond to higher energy levels, situated farther from the nucleus.
Angular Momentum Quantum Number
- When \( l = 0 \), the orbital is spherically shaped (s-orbital).
- When \( l = 1 \), the orbital has a dumbbell shape (p-orbital).
- When \( l = 2 \), it represents more complex shapes (d-orbital).
- When \( l = 3 \), the orbital further increases in complexity, representing an f-orbital.
Magnetic Quantum Number
- For an f-orbital where \( l = 3 \), \( m \) can be -3, -2, -1, 0, 1, 2, or 3.
Spin Quantum Number
- These values represent the two possible spin states of an electron: "up" and "down."