Chapter 2: Problem 106
What is the wavelength of the radiation emitted produced in a line in the Lyman series when an electron falls from fourth stationary state in hydrogen atom? \(\left(\mathrm{R}_{\mathrm{H}}=1.1 \times 10^{7} \mathrm{~m}^{-1}\right)\) (a) \(96.97 \mathrm{~nm}\) (b) \(969.7 \mathrm{~nm}\) (c) \(9.697 \mathrm{~nm}\) (d) None of these
Short Answer
Step by step solution
Understanding the Lyman Series
Using the Rydberg Formula
Plug in the Quantum Levels
Calculate the Energy Difference
Calculate the Wavelength Inverse
Find the Wavelength
Convert Wavelength to Nanometers
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rydberg Formula
Hydrogen Atom
- The electron transitions between these levels correspond to spectral lines that we can observe.
- Each transition is associated with a specific amount of energy, often visualized using an energy level diagram called the Bohr model.
Spectral Lines
- In the case of hydrogen, the spectral lines result from the electron's movement between quantum levels.
- Spectral lines are not only vital for understanding atomic structure but also for identifying elements in stars and galaxies.
Quantum Levels
- For hydrogen, these levels are defined by quantum numbers, denoted by \(n\).
- The lowest energy state is the ground state, and any higher state is called an excited state.