Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which is an incorrect statement regarding oxymercuration-demercuration? (a) Here rearrangement takes place (b) In the second step demercuration occurs that is, \(\mathrm{NaBH}_{4}\) reduces- \(\mathrm{HgOAc}_{2}\) group to hydrogen(c) The net reaction is addition of water according to Markovnikov's rule (d) In the first step oxymercuration occurs, that is, water and \(\mathrm{Hg}(\mathrm{OAc})_{2}\) add to double bond

Short Answer

Expert verified
The incorrect statement is (a), as oxymercuration-demercuration occurs without rearrangement.

Step by step solution

01

Understand Oxymercuration-Demercuration

Oxymercuration-demercuration is a two-step chemical reaction that converts an alkene into an alcohol without rearrangement. In the first step, oxymercuration, the alkene reacts with mercuric acetate (Hg(OAc)_2) followed by water, resulting in an organomercury intermediate. The second step, demercuration, involves reducing the mercury element using sodium borohydride (NaBH_4) to get the final alcohol product.
02

Evaluate Statement (a)

Statement (a) claims that rearrangement occurs during the reaction. However, oxymercuration-demercuration is known for proceeding without carbocation rearrangement, which is one of its main advantages over other hydration reactions.
03

Evaluate Statement (b)

Statement (b) correctly describes the demercuration step where the organomercury compound is reduced by NaBH_4, replacing the HgOAc group with hydrogen, completing the conversion to an alcohol.
04

Evaluate Statement (c)

Statement (c) is accurate as oxymercuration-demercuration results in Markovnikov addition of water across the double bond, where the OH group is added to the more substituted carbon atom.
05

Evaluate Statement (d)

Statement (d) correctly describes the first step, oxymercuration, where Hg(OAc)_2 and water add across the alkene's double bond to form the organomercury intermediate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Markovnikov's Rule
Markovnikov's Rule is a guiding principle in organic chemistry that predicts the outcome of certain addition reactions, particularly for alkenes. According to the rule, when you add a protic acid (an acid that can donate protons) to an unsymmetrical alkene, the hydrogen atom of the acid bonds to the carbon with more hydrogen atoms already attached, and the other part of the acid, such as a halide or a hydroxyl group, bonds to the carbon with fewer hydrogen atoms.
This rule helps chemists predict which isomer will be formed when different reactions occur.
  • In the context of oxymercuration-demercuration, Markovnikov's Rule is followed because the hydroxyl group ( OH) ends up on the more substituted carbon atom of the originally present double bond.
  • The advantage of this reaction is that it allows transformation without the rearrangement of carbon atoms, which is often a problem in other hydration reactions that progress via carbocations.
This predictable outcome of Markovnikov's Rule makes these types of reactions very useful in synthetic organic chemistry, allowing scientists to produce specific isomers that might be necessary for a particular application.
Carbocation Rearrangement
Carbocation rearrangement is a significant consideration in many chemical reactions that involve carbocations as intermediates. A carbocation is an ion with a positively charged carbon atom. These are generally unstable and in many reactions will attempt to rearrange to a more stable state, typically becoming more substituted during the course of the reaction.
However, in the case of oxymercuration-demercuration, this rearrangement does not occur. This is because the reaction does not form a free carbocation. Instead, it forms a bridge-like intermediate, where the mercury element stabilizes the structure.
  • This feature is beneficial because it ensures the reaction progresses predictably, adhering to Markovnikov's Rule without resulting in unexpected rearrangements of the carbon skeleton.
  • Because of the absence of carbocation rearrangement, oxymercuration-demercuration is often preferred in a synthetic setting over reactions that proceed through a carbocation, such as direct hydration using sulfuric acid, which can produce different isomers.
By avoiding carbocation rearrangements, chemists can consistently achieve the desired chemical structure without the risk of creating multiple by-products.
Hydration of Alkenes
Hydration of alkenes is a common reaction in organic chemistry where water is added to a carbon-carbon double bond (alkene) to form an alcohol. This reaction is crucial in converting alkenes into more functional alcohols, which are valuable intermediates in synthesis.
One of the traditional methods of hydrating alkenes involves the direct use of water in the presence of an acid catalyst. However, this can lead to carbocation rearrangements and thus a mixture of products. This is where oxymercuration-demercuration becomes advantageous:
  • Oxymercuration: Involves using mercuric acetate and water to add across the double bond, without forming a free carbocation, thereby avoiding rearrangements.
  • Demercuration: Uses sodium borohydride to replace the mercury intermediate with hydrogen, completing the transformation into an alcohol while maintaining the integrity of the carbon framework.
This method ensures the Markovnikov addition of water to the alkene, where the hydroxyl group ends up on the more substituted carbon atom, providing a cleaner and more straightforward approach to synthesizing alcohols from alkenes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A hydrocarbon of molecular formula \(\mathrm{C}_{7} \mathrm{H}_{12}\) on catalytic hydrogenation over platinum gives \(\mathrm{C}_{7} \mathrm{H}_{16}\). The parent hydrocarbon adds bromine and also reacts with \(\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right] \mathrm{OH}\) to give a precipitate. The parent hydrocarbon is: (a) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}_{2} \mathrm{C} \equiv \mathrm{CH}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{2} \mathrm{CH}=\mathrm{CH}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CCH}\left(\mathrm{CH}_{3}\right)_{2}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}=\mathrm{CHCH}_{3}\)

Ozonolysis of 2,3 -dimethyl-1-butene followed by reduction with zinc and water gives: (a) Methanoic acid and 3-methyl-2-butanone (b) Methanal and 3-methyl-2-butanone (c) Methanal and 2-methyl-3-butanone (d) Methanoic acid and 2 -methyl-3-butanone

Which among the following reagents converts cyclohexene into trans diol? (a) Baeyer reagent (b) \(\mathrm{OsO}_{4}\) (c) \(\mathrm{I}_{2} / \mathrm{CH}_{3} \mathrm{COOAg}\) (wet) (d) \(\mathrm{I}_{2} / \mathrm{CH}_{3} \mathrm{COOAg}\) (dry)

Which one of these is not compatible with arenes? (a) Greater stability (b) Resonance (c) Delocalization of \(\pi\) -electrons (d) Electrophillic addition

Which of the reagents on reaction with cyclohexanol gives best yield of cyclohexene? (a) Conc. \(\mathrm{H}_{3} \mathrm{PO}_{4}\) (b) Conc. HCl (c) Conc. \(\mathrm{HBr}\) (d) Conc. HCl with \(\mathrm{ZnCl}_{2}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free