Chapter 11: Problem 72
The most stable free radical among the following is (1) \(\mathrm{C}_{6} \mathrm{H}_{5} \cdot \mathrm{CH}_{2}\) (2) \(\mathrm{CH}_{3}-\cdot \mathrm{CH}-\mathrm{CH}_{3}\) (3) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHCH}_{3}\) (4) \(\mathrm{CH}_{3} \cdot \mathrm{CH}_{2}\) (a) \(3>1>4>2\) (b) \(1>3>2>4\) (c) \(3>1>2>4\) (d) \(3>2>1>4\)
Short Answer
Step by step solution
Understanding Free Radical Stability
Analyzing Each Radical
Ranking Order Based on Stability
Selecting the Correct Option
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Resonance Stabilization
In the case of the allylic radical, resonance allows the unpaired electron to distribute over a conjugated system. The conjugated system of alternating single and double bonds offers a wider space for electron delocalization. As a result, a molecule with a structure that enables resonance will usually have greater stability. Therefore, when comparing the stability of free radicals, molecules benefitting from resonance stabilization are generally more stable than those relying on other stabilizing factors.
Hyperconjugation
Consider secondary radicals like \( \mathrm{CH}_3-\cdot \mathrm{CH}-\mathrm{CH}_3 \). Here, hydrogen atoms from adjacent C-H bonds contribute to hyperconjugative stabilization. More adjacent bonds enhance such stabilization, distributing the electron's energy and lowering the radical’s overall energy.
Nonetheless, while hyperconjugation provides a degree of stability, it is not as effective as resonance stabilization. Thus, radicals relying solely on hyperconjugation are typically less stable compared to those benefitting from resonance.
Alkyl Radicals
This order is primarily because secondary and tertiary carbons can gain stability through both hyperconjugation and inductive effects. Secondary radicals like \( \mathrm{CH}_3-\cdot \mathrm{CH}-\mathrm{CH}_3 \) are more stable than primary radicals due to having more adjacent bonds contributing to hyperconjugation. Tertiary radicals have even more such interactions, often resulting in substantial stability.
Primary radicals, such as \( \mathrm{CH}_3 \cdot \mathrm{CH}_2 \), have limited stabilization options as they rely less on hyperconjugation and do not benefit significantly from inductive effects. This makes them the least stable among alkyl radicals.
Inductive Effects
For secondary radicals, such as \( \mathrm{CH}_3-\cdot \mathrm{CH}-\mathrm{CH}_3 \), inductive effects can enhance stability, albeit to a lesser extent compared to resonance. Alkyl groups, which are slightly electron-donating, can push electron density towards the radical center, stabilizing it. The more alkyl groups surrounding the radical center, the greater the inductive stabilization.
Despite this, consider that while inductive effects contribute to stability, they are usually overpowered by other effects such as resonance, especially in systems where resonance is possible. Thus, in a comparative context, free radicals that are stabilized by resonance are generally more stable than those relying on inductive effects alone.