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What is \(\mathrm{X}\) in the following reaction? \(\mathrm{SiCl}_{4}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{X}+\mathrm{HCl}\) (a) \(\mathrm{H}_{4} \mathrm{SiO}_{4}\) (b) \(\mathrm{SiH}_{4}\) (c) \((\mathrm{SiOOH})_{2}\) (d) \(\mathrm{Si}\left(\mathrm{ClO}_{4}\right)_{4}\)

Short Answer

Expert verified
The compound \(\mathrm{X}\) is \(\mathrm{H}_4 \mathrm{SiO}_4\). (Option a)

Step by step solution

01

Identify the reactants and products

The given chemical equation is \(\mathrm{SiCl}_4 + \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{X} + \mathrm{HCl}\). \(\mathrm{SiCl}_4\) and \(\mathrm{H}_2 \mathrm{O}\) are reactants that yield \(\mathrm{X}\) and \(\mathrm{HCl}\). We need to identify what \(\mathrm{X}\) is.
02

Consider the reaction type

This is a hydrolysis reaction where \(\mathrm{SiCl}_4\), silicon tetrachloride, reacts with water. Typically, this results in the formation of silicic acid, as \(\mathrm{HCl}\) is produced.
03

Use hydrolysis knowledge to predict \(\mathrm{X}\)

Silicon tetrachloride \((\mathrm{SiCl}_4)\) typically hydrolyzes in water to form silicic acid \((\mathrm{H}_4 \mathrm{SiO}_4)\) and hydrochloric acid \((\mathrm{HCl})\). The equation can be balanced to verify, but this substance is a common product of such a reaction.
04

Compare with the given options

We determined that \(\mathrm{X}\) is likely \(\mathrm{H}_4 \mathrm{SiO}_4\), matching option (a). The other options \((\mathrm{SiH}_4\), \((\mathrm{SiOOH})_2\), \(\mathrm{Si} (\mathrm{ClO}_4)_4\)) don't typically result from the hydrolysis of \(\mathrm{SiCl}_4\).
05

Conclude identification of \(\mathrm{X}\)

Based on the typical product of \(\mathrm{SiCl}_4\) hydrolysis, option (a) \((\mathrm{H}_4 \mathrm{SiO}_4)\) is the correct identity for \(\mathrm{X}\) in the reaction given.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Silicon Tetrachloride
Silicon tetrachloride (\(\mathrm{SiCl}_{4}\)) is a colorless liquid at room temperature. It is commonly used in chemical reactions due to its ability to react vigorously with water. This chemical compound is a derivative of silicon, where silicon is bound to four chlorine atoms. Its high reactivity with water makes it an interesting candidate for studying hydrolysis reactions. Such reactivity is capitalized in industrial processes, especially in the manufacturing of high-purity silicon for electronics. Due to the presence of chlorine atoms, \(\mathrm{SiCl}_{4}\) should be handled carefully, as it can release hydrochloric acid (\(\mathrm{HCl}\)) upon exposure to moisture in the air. This makes understanding its chemical behavior crucial not only in laboratory experiments but also in precision-driven industrial applications.
Silicic Acid
Silicic acid (\(\mathrm{H}_{4} \mathrm{SiO}_{4}\)) is a compound that commonly results from the hydrolysis of silicon tetrachloride. It forms when water reacts with silicon compounds, breaking silicon-halogen bonds to form the more stable silicon-oxygen bonds. This transformation is a classic example of hydrolysis, where water molecules contribute to the breakdown of a substance. Silicic acid itself is not usually isolated in pure form because it tends to condense into silica or other polysilicates.
As a weak acidic compound, silicic acid contains silicon atoms bonded to hydroxyl groups, resulting in silanol groups. These silanol groups are highly reactive and often lead to the formation of silicate minerals in nature. In industrial contexts, understanding its formation and stability is crucial for the production of various silicon-based materials, used in everything from construction to electronics.
Chemical Equations
Chemical equations are symbolic representations of chemical reactions. They provide a clear and concise way to depict the reactants and products of a reaction. In the case of \(\mathrm{SiCl}_{4} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{H}_{4} \mathrm{SiO}_{4} + \mathrm{HCl}\), the equation shows that silicon tetrachloride reacts with water to produce silicic acid and hydrochloric acid. It's a balanced reaction that reflects the conservation of mass, meaning the number of each type of atom on the reactant side equals that on the product side.
Writing and balancing chemical equations require a basic understanding of the stoichiometry involved. Each coefficient in a balanced equation indicates the necessary proportion between different substances. This is essential for scientists and engineers to predict how much of each substance is required or produced in a reaction. In educational contexts, practicing chemical equation balancing enhances one's ability to visualize and quantify chemical changes, fostering a deeper comprehension of chemistry's foundational principles.

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Most popular questions from this chapter

Aluminium chloride in acidified aqueous solution forms: (a) Octahedral \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{+3}\) ion (b) Tetrahedral \(\left.[\mathrm{A}]\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{+3}\) ion (c) Octahedral \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{+3}\) ion (d) Tetrahedral \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{+3}\) ion

Which of the following is only acidic in nature? (a) \(\mathrm{B}(\mathrm{OH})_{3}\) (b) \(\mathrm{Al}(\mathrm{OH})_{3}\) (c) \(\mathrm{Be}(\mathrm{OH})_{2}\) (d) \(\mathrm{Mg}(\mathrm{OH})_{2}\)

The structure of diborane \(\left(\mathrm{B}_{2} \mathrm{H}_{6}\right)\) contains (a) Four 2c-2e bonds and two \(3 \mathrm{c}-2 \mathrm{e}\) bonds (b) Two \(2 \mathrm{c}-2 \mathrm{e}\) bonds and four \(3 \mathrm{c}-2 \mathrm{e}\) bonds (c) Two \(2 \mathrm{c}-2 \mathrm{e}\) bonds and two \(3 \mathrm{c}-3 \mathrm{e}\) bonds (d) Four \(2 \mathrm{c}-2 \mathrm{e}\) bonds and four \(3 \mathrm{c}-2 \mathrm{e}\) bonds

Boron halides behave as Lewis acids because they (a) Have only six electron in the valence shell (b) Have a lone pair of electrons on the \(\mathrm{B}\) atom (c) Are covalent compounds (d) Are ionic compounds

The aqueous solution of an inorganic compound \((X)\) gives white precipitate with \(\mathrm{NH}_{4} \mathrm{OH}\) which does not dissolve in excess of \(\mathrm{NH}_{4} \mathrm{OH}\). This aqueous solution also gives white precipitate with \(\mathrm{AgNO}_{3}\) and the precipitate is soluble in dilute \(\mathrm{HNO}_{3} .\) Here \((\mathrm{X})\) is: (a) \(\mathrm{AlCl}_{3}\) (b) \(\mathrm{AlBr}_{3}\) (c) \(\mathrm{AlN}\) (d) \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\)

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