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Boron compounds behave as lewis acids because of their (a) Ionisation energy (b) Electron deficient nature (c) Covalent nature (d) Ionisation energy

Short Answer

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Boron compounds behave as Lewis acids due to their (b) electron deficient nature.

Step by step solution

01

Understanding Lewis Acids

Lewis acids are chemical compounds that can accept a pair of electrons due to an empty orbital or a positive charge. They are generally electron-deficient.
02

Studying Boron Compounds

Boron compounds often have an incomplete octet and are electron-deficient. This property makes them capable to accept electrons, behaving as Lewis acids.
03

Analyzing Options

Given the options: (a) and (d) both refer to ionization energy, which is not related to their nature as Lewis acids. (c) Covalent nature does not lead to electron deficiency specifically. The correct attribute due to which they behave as Lewis acids is (b) Electron deficient nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boron Compounds
Boron compounds play a vital role in chemistry due to their unique properties and the central position of boron in the periodic table. Boron is a metalloid, meaning it exhibits characteristics of both metals and non-metals. The most fascinating feature of boron compounds is their ability to form strong covalent bonds.
These bonds emerge because boron typically forms compounds by sharing its three valence electrons. This sharing results in the formation of diverse structures, such as boranes and borates. Boron is also known for its ability to form stable complexes with other elements due to its bonding versatility.
  • These compounds are widely used in industry and research, serving as catalysts, reagents, and building blocks for complex molecular architectures.
  • Boron compounds play a role in fields ranging from pharmaceuticals to advanced materials science.
Its attributes, including bond strength and ability to coordinate with other substances, make boron compounds crucial in many chemical reactions.
Electron Deficient
An electron-deficient compound lacks a sufficient number of electrons needed to form a stable electron pair on its atoms. This situation typically arises in compounds formed by elements like boron and aluminum, which have fewer than eight electrons in their outer shell.
When discussing boron, its outer electron shell contains only three electrons, allowing it to make three bonds. However, to achieve a stable electron configuration, an atom usually aims to have a complete octet. Yet boron often does not reach this complete state through bonding.
  • This electron deficiency is what makes boron compounds strong Lewis acids. They readily accept electron pairs to fill this shell.
  • In practical applications, this ability is leveraged to facilitate reactions, as boron can stabilize reactive intermediates or enhance reaction mechanisms by accepting electrons.
Understanding electron deficiency helps us predict how boron compounds will react in various chemical environments.
Incomplete Octet
The concept of an incomplete octet is central to understanding why certain compounds behave the way they do. Atoms generally aim to achieve an octet configuration, which is associated with stability. However, not all atoms can achieve this due to their inherent paucity of electrons.
In the context of boron, the incomplete octet means that boron compounds have fewer than eight electrons in their valence shell even after forming bonds. This leaves them with an ability to still accommodate additional electrons from other atoms or molecules.
  • This capability makes boron compounds excellent candidates for participation in chemical reactions.
  • Since they can accept electron pairs, they act as electron pair acceptors in these reactions, defining their behavior as Lewis acids.
Recognizing the role of an incomplete octet is crucial when predicting and explaining the reactivity patterns of boron compounds.

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Most popular questions from this chapter

Select the correct statements about diborane. (1) Hb ....B....Hb bond angle is \(122^{\circ}\) (2) All hydrogen in \(\mathrm{B}_{2} \mathrm{H}_{6}\) lie in the same plane (3) Each boron atom lies in sp \(^{3}\) hybrid state (4) \(\mathrm{B}_{2} \mathrm{H}_{6}\) has three centered bond (a) \(1,2,3\) (b) \(1,3,4\) (c) \(2,3,4\) (d) 1,4

\(\mathrm{H}_{3} \mathrm{BO}_{3}\) is: (a) Monobasic and weak Lewis acid. (b) Monobasic and weak bronsted acid. (c) Monobasic and strong lewis acid. (d) Tribasic and weak bronsted acid.

\(\mathrm{BF}_{3}\) used as a catalyst in several industrial processes due to its (a) Weak reducing action (b) Strong reducing nature (c) Weak lewis acid character (d) Reducing nature

\(\mathrm{X}\) reacts with aqueous \(\mathrm{NaOH}\) solution to form \(\mathrm{Y}\) and \(\mathrm{H}_{2}\). Aqueous solution of \(\mathrm{Y}\) is heated to \(323-333 \mathrm{~K}\) and on passing \(\mathrm{CO}_{2}\) into it, \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) and \(\mathrm{Z}\) were formed. When \(Z\) is heated to \(1200^{\circ} \mathrm{C}, \mathrm{Al}_{2} \mathrm{O}_{3}\) is formed. \(\mathrm{X}, \mathrm{Y}\) and \(\mathrm{Z}\) respectively are (a) \(\mathrm{Al}, \mathrm{Al}(\mathrm{OH})_{3}, \mathrm{AlCl}_{3}\) (b) \(\mathrm{Al}, \mathrm{NaAlO}_{2}, \mathrm{Al}(\mathrm{OH})_{3}\) (c) \(\mathrm{Zn}, \mathrm{Na}_{2} \mathrm{ZnO}_{2}, \mathrm{Al}(\mathrm{OH})_{3}\) (d) \(\mathrm{Al}, \mathrm{AlCl}_{3}, \mathrm{NaAlO}_{2}\)

Which of the following does not exist in free state? (a) \(\mathrm{BCl}_{3}\) (b) \(\mathrm{BH}_{3}\) (c) \(\mathrm{BF}_{3}\) (d) \(\mathrm{BBr}_{3}\)

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