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The volume of \(1.0 \mathrm{~g}\) of hydrogen in litres at NTP is: (a) \(22.4 \mathrm{~L}\) (b) \(1.12 \mathrm{~L}\) (c) \(11.2 \mathrm{~L}\) (d) \(44.56 \mathrm{~L}\)

Short Answer

Expert verified
The volume of 1 gram of hydrogen at NTP is 11.2 L, answer (c).

Step by step solution

01

Understanding NTP

NTP stands for Normal Temperature and Pressure. At NTP, the conditions are defined as a temperature of 0°C (273.15 K) and a pressure of 1 atm.
02

Using Molar Volume Concept

At NTP, 1 mole of any ideal gas occupies a volume of 22.4 liters. This is an important principle to remember for calculations involving gases.
03

Calculating Moles of Hydrogen

To find out how many moles are present in 1 gram of hydrogen, use the molar mass of hydrogen, which is approximately 2 g/mol (since a hydrogen molecule is H₂). Thus, the number of moles is calculated as: \[ \text{Number of moles} = \frac{1.0 \text{ g}}{2 \text{ g/mol}} = 0.5 \text{ moles} \]
04

Determining Volume of Hydrogen Gas

Using the concept from Step 2, where 1 mole of hydrogen gas at NTP occupies 22.4 L, the volume for 0.5 moles can be calculated as: \[ \text{Volume} = 0.5 \text{ moles} \times 22.4 \text{ L/mole} = 11.2 \text{ L} \]
05

Choosing the Correct Answer

Based on the calculation, the volume of 1 gram of hydrogen at NTP is 11.2 liters. Therefore, the correct answer is (c) 11.2 L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Volume
The concept of molar volume is crucial when dealing with gases in chemistry. Molar volume refers to the volume occupied by one mole of any substance in its gaseous state. This is a consistent value when we're talking about ideal gases at specific conditions. For ideal gases at Normal Temperature and Pressure (NTP), which is a standard set of state conditions, the molar volume is always the same: 22.4 liters.
This figure is derived from the Ideal Gas Law, a fundamental principle in chemistry that connects pressure, volume, temperature, and moles of a gas through the equation: \( PV = nRT \). Here, \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the gas constant, and \( T \) is temperature.
Knowing that 22.4 liters is the volume one mole of any ideal gas occupies at NTP allows you to easily determine the volume that any given number of moles will occupy, simply by multiplying the number of moles by 22.4 L/mol. This property simplifies calculations in chemistry when working under these standard conditions.
NTP (Normal Temperature and Pressure)
NTP is an acronym for Normal Temperature and Pressure, which serves as a baseline to standardize measurements across laboratories worldwide. At NTP, the conditions are set at a temperature of 0°C (which is equivalent to 273.15 K) and a pressure of 1 atmosphere (atm). These conditions mirror those naturally found in some environmental zones on Earth, providing a realistic basis for many experiments and calculations relating to gases.
Under NTP conditions, the behavior of gases becomes particularly predictable. It's important to understand that these conditions are different from STP (Standard Temperature and Pressure), which may have slightly different parameters depending on the scientific context.
  • 0°C means all thermodynamic calculations begin from this freezing point of water.
  • 1 atm is a standard pressure, helping to ensure gas pressure is at a common baseline.
This makes NTP a very useful reference point when discussing molar volume and other gas-related properties, ensuring consistency and accuracy in experimental calculations.
Mole Concept
The mole concept is foundational in chemistry, providing a way to quantify atoms, molecules, and ions. A mole is defined as exactly 6.022 x 1023 particles, known as Avogadro's number.
This large number is used because atoms and molecules are incredibly tiny. By using moles, chemists can work with manageable numbers instead of unwieldy quantities.
Moles link directly to the mass of a substance, as seen in the exercise where 1 gram of hydrogen is converted into moles using its molar mass. The molar mass is the mass of one mole of a substance expressed in grams per mole (g/mol). For hydrogen gas (H2), the molar mass is about 2 g/mol because each hydrogen atom has an approximate mass of 1 u, and there are two atoms in a molecule of hydrogen gas. This makes conversions between mass and moles straightforward: you divide the mass of the substance by its molar mass.
With these conversions, you can then use other concepts like molar volume to find the properties of gases under certain conditions. Thus, the mole concept serves as a bridge connecting the atomic scale to the scale we experience daily.

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Most popular questions from this chapter

If equal moles of water and urea are taken in a vessel what will be the mass percentage of urea in the solution? (a) \(22.086\) (b) \(11.536\) (c) \(46.146\) (d) \(23.076\)

If we consider that \(\frac{1}{6}\), in place of \(\frac{1}{12}\), mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will: (a) Decrease twice (b) Increase two fold (c) Remain unchanged (d) Be a function of the molecular mass of the substance

Mixture \(\mathrm{X}=0.02 \mathrm{~mol}\) of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SO}_{4}\right] \mathrm{Br}\) and \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Br}\right] \mathrm{SO}_{4}\) was prepared in 2 litre of solution. 1 litre of mixture \(\mathrm{X}+\mathrm{excess} \mathrm{AgNO}_{3} \longrightarrow \mathrm{Y}\) 1 litre of mixture \(\mathrm{X}+\) excess \(\mathrm{BaCl}_{2} \longrightarrow \mathrm{Z}\) Number of moles of \(\mathrm{Y}\) and \(\mathrm{Z}\) are: (a) \(0.02,0.01\) (b) \(0.01,0.01\) (c) \(0.01,0.02\) (d) \(0.02,0.02\)

The normality of orthophosphoric acid having purity of \(70 \%\) be weight and specific gravity \(1.54\) is: (a) \(11 \mathrm{~N}\) (b) \(22 \mathrm{~N}\) (c) \(33 \mathrm{~N}\) (d) \(44 \mathrm{~N}\)

If \(3.02 \times 10^{19}\) molecules are removed from \(98 \mathrm{mg}\) of \(\mathrm{H}_{2} \mathrm{SO}_{4}\), then the number of moles of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) left are: (a) \(0.1 \times 10^{-3}\) (b) \(5 \times 10^{-4}\) (c) \(1.2 \times 10^{-4}\) (d) \(1.5 \times 10^{-3}\)

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