Chapter 8: Problem 32
What changes in the oxidation numbers occur when copper reacts with concentrated nitric acid to give a blue solution and a brown acidic gas? (1) \(\mathrm{Cu}(0)\) to \(\mathrm{cu}(\mathrm{II})\) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}\) (IV) (2) \(\mathrm{Cu}(0)\) to \(\mathrm{Cu}(\mathrm{II})\) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}(\mathrm{III})\) (3) \(\mathrm{Cu}\) (I) to \(\mathrm{Cu}\) (II) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}\) (IV) (4) \(\mathrm{Cu}\) (II) to \(\mathrm{Cu}\) (I) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}\) (IV)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
oxidation state changes
For example, in the reaction between copper and concentrated nitric acid, copper starts with an oxidation state of 0 and changes to +2. This indicates that copper has lost two electrons. Similarly, the nitrogen in nitric acid (HNO₃) changes from an oxidation state of +5 to +4. This means nitrogen gains one electron. Recognizing these changes is crucial to identify redox reactions.
copper reactions
Copper, in its metallic state, has an oxidation number of 0. In the presence of nitric acid, copper is oxidized to form Cu²⁺, with an oxidation number of +2. This shift from 0 to +2 means copper loses two electrons during the reaction.
The visible change to a blue solution indicates the formation of copper(II) ions, which are soluble in water.
nitric acid reactions
In the reaction with copper, the nitric acid provides nitrate ions (NO₃⁻), where nitrogen has an oxidation state of +5. Upon reaction, nitrogen dioxide (NO₂) is produced, where nitrogen's oxidation state is +4.
This reduction from +5 to +4 shows that nitrogen gains an electron during the reaction. The evolution of a brown gas further confirms the presence of nitrogen dioxide.
redox reactions
In our example, copper is oxidized from an oxidation state of 0 to +2, meaning it loses two electrons. Simultaneously, nitrogen in nitric acid is reduced from +5 to +4, gaining an electron.
Such reactions are vital in many chemical processes and industrial applications. They help understand how materials change and react, enabling us to predict and manipulate chemical behavior.