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What changes in the oxidation numbers occur when copper reacts with concentrated nitric acid to give a blue solution and a brown acidic gas? (1) \(\mathrm{Cu}(0)\) to \(\mathrm{cu}(\mathrm{II})\) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}\) (IV) (2) \(\mathrm{Cu}(0)\) to \(\mathrm{Cu}(\mathrm{II})\) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}(\mathrm{III})\) (3) \(\mathrm{Cu}\) (I) to \(\mathrm{Cu}\) (II) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}\) (IV) (4) \(\mathrm{Cu}\) (II) to \(\mathrm{Cu}\) (I) and \(\mathrm{N}(\mathrm{V})\) to \(\mathrm{N}\) (IV)

Short Answer

Expert verified
The correct option is (1).

Step by step solution

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01

- Identify the Reactants and Products

The reaction involves copper (Cu) reacting with concentrated nitric acid (HNO₃). The products are a blue solution and a brown acidic gas. The blue solution indicates the presence of copper(II) ions (Cu²⁺) and the brown gas is nitrogen dioxide (NO₂).
02

- Determine Oxidation Numbers of Copper

Initially, copper is in its elemental state with an oxidation number of 0. When copper forms Cu²⁺, its oxidation number changes to +2. So, the change is from 0 to +2.
03

- Determine Oxidation Numbers of Nitrogen

In concentrated nitric acid, nitrogen is usually in the form of nitrate (NO₃⁻), where nitrogen has an oxidation number of +5. The product nitrogen dioxide (NO₂) has nitrogen with an oxidation number of +4. Thus, the change is from +5 to +4.
04

- Analyze the Given Options

From the identified changes: Cu(0) to Cu(II) is a change from 0 to +2, and N(V) to N(IV) is a change from +5 to +4. The correct changes match with option (1).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

oxidation state changes
Understanding oxidation states helps us track electron transfers in a chemical reaction. An oxidation state is a hypothetical charge that an atom would have if all bonds to atoms of different elements were fully ionic. In a reaction, the oxidation state of an element can increase (oxidation) or decrease (reduction).

For example, in the reaction between copper and concentrated nitric acid, copper starts with an oxidation state of 0 and changes to +2. This indicates that copper has lost two electrons. Similarly, the nitrogen in nitric acid (HNO₃) changes from an oxidation state of +5 to +4. This means nitrogen gains one electron. Recognizing these changes is crucial to identify redox reactions.
copper reactions
Copper is a versatile metal that undergoes interesting chemical changes. When copper reacts with concentrated nitric acid, it forms a blue solution (copper(II) ions) and a brown acidic gas (nitrogen dioxide).

Copper, in its metallic state, has an oxidation number of 0. In the presence of nitric acid, copper is oxidized to form Cu²⁺, with an oxidation number of +2. This shift from 0 to +2 means copper loses two electrons during the reaction.

The visible change to a blue solution indicates the formation of copper(II) ions, which are soluble in water.
nitric acid reactions
Nitric acid is a powerful oxidizing agent often used in redox reactions. When concentrated nitric acid reacts with metals, it typically leads to the formation of nitrogen dioxide (NO₂) and other nitrogen oxides.

In the reaction with copper, the nitric acid provides nitrate ions (NO₃⁻), where nitrogen has an oxidation state of +5. Upon reaction, nitrogen dioxide (NO₂) is produced, where nitrogen's oxidation state is +4.

This reduction from +5 to +4 shows that nitrogen gains an electron during the reaction. The evolution of a brown gas further confirms the presence of nitrogen dioxide.
redox reactions
Redox reactions, short for reduction-oxidation reactions, involve the transfer of electrons between substances. One substance loses electrons (oxidation), while another gains electrons (reduction).

In our example, copper is oxidized from an oxidation state of 0 to +2, meaning it loses two electrons. Simultaneously, nitrogen in nitric acid is reduced from +5 to +4, gaining an electron.

Such reactions are vital in many chemical processes and industrial applications. They help understand how materials change and react, enabling us to predict and manipulate chemical behavior.

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Most popular questions from this chapter

Which statement is incorrect? (1) Oxidation of a substance is followed by reduction of another. (2) Reduction of a substance is followed by oxidation of another. (3) Oxidation and reduction are complimentary reactions. (4) It is not necessary that both oxidation and reduction should takes place in the same reaction.

Standard reduction potential of an clement is cqual to (1) \(+\mathrm{l} \times\) its reduction potential (2) \(-1 \times\) its standard oxidation potential (3) \(0.00\) (4) \(+\mathrm{l} \times\) its standard oxidation potential

Addition of zinc powder to copper sulphate solution precipitates copper due to (1) Reduetion of \(\mathrm{Cu}^{2+}\) (2) Reduction of \(\mathrm{SO}_{4}^{2-}\) (3) Reduction of \(\mathrm{Zn}^{2+}\) (4) Hydrolysis of \(\mathrm{CuSO}_{4}\)

Which of the following is a redox reaction? (1) \(\mathrm{AlH}_{3}(\mathrm{~g})+\mathrm{H}^{-}(\mathrm{g}) \longrightarrow \mathrm{A} \mathrm{lH}_{4}^{-}(\mathrm{g})\) (2) \(\mathrm{Al}_{2} \mathrm{Cl}_{6}(\mathrm{~g}) \longrightarrow \mathrm{AlCl}_{3}(\mathrm{~g})\) (3) \(\mathrm{Al}^{3+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \longrightarrow \mathrm{Al}(\mathrm{OH})_{3}(\mathrm{~s})\) (4) \(2 \mathrm{Al}_{(\mathrm{s})}+3 \mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{~A} 1 \mathrm{Cl}_{3}(\mathrm{~g})\)

When zinc is kept in \(\mathrm{CuSO}_{4}\) solution copper gets precipitated because (1) Standard reduction potential of zinc is more than copper (2) Standard reduction potential of zinc is less than copper (3) Atomic number of zinc is larger than copper (4) Atomic number of zinc is lower than copper

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