Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) by \(\mathrm{O}_{2}\) is an cxothermic reaction. The yicld of \(\mathrm{SO}_{3}\) will be maximum when(1) Temperature is increased and pressure is kept constant. (2) Temperature is reduced and pressure is increased. (3) Both temperature and pressure are increased. (4) Both temperature and pressure are reduced.

Short Answer

Expert verified
Option 2: Temperature is reduced and pressure is increased.

Step by step solution

01

Understand the Reaction

The oxidation of \(\text{SO}_2\) to \(\text{SO}_3\) by \(\text{O}_2\) is expressed by the following exothermic reaction equation: 2\(\text{SO}_2 + \text{O}_2} \rightarrow 2\text{SO}_3 \). In this reaction, heat is released.
02

Consider Le Chatelier's Principle

Le Chatelier's Principle states that if a system at equilibrium is disturbed, the system will adjust itself to counteract the disturbance and restore a new equilibrium. An exothermic reaction will shift towards the reactants if the temperature is increased. Hence, lower temperatures favor the formation of products.
03

Analyze the Effect of Pressure

The reaction involves a decrease in the number of moles of gas (3 moles of gas reactants to 2 moles of gas products). According to Le Chatelier's Principle, increasing pressure will shift the equilibrium towards the side with fewer moles of gas, favoring the formation of \(\text{SO}_3\).
04

Determine the Optimal Conditions

To maximize the yield of \(\text{SO}_3\), we need conditions that favor the formation of the product. Therefore, a decrease in temperature and an increase in pressure will maximize the yield of \(\text{SO}_3\). Based on the given options, the correct answer is option 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation Reaction
Oxidation reactions involve the transfer of electrons between substances. In the reaction we are studying, sulfur dioxide (SO₂) is oxidized to sulfur trioxide (SO₃). The simplified reaction is represented as:

2SO₂ + O₂ → 2SO₃

In this process, sulfur (in SO₂) increases its oxidation state from +4 to +6 in SO₃. For oxidation reactions, the substance that gains oxygen or loses electrons is oxidized, while the substance that loses oxygen or gains electrons is reduced. Here, SO₂ is oxidized to SO₃, and O₂ is reduced.
Exothermic Reaction
An exothermic reaction is one that releases heat into the surroundings. The oxidation of SO₂ to SO₃ is an exothermic reaction. During the reaction, energy is released which often makes the surrounding environment feel warmer.

One important characteristic of exothermic reactions is that they tend to have lower energy products compared to the reactants. This energy difference is released as heat. The reaction can be presented in the form:

2SO₂ + O₂ → 2SO₃ + heat

Because heat is released, this favors lower temperatures for product formation according to Le Chatelier's Principle.
Equilibrium Shift
Equilibrium in a chemical reaction occurs when the rate of the forward reaction equals the rate of the reverse reaction. The reaction of SO₂ to SO₃ reaches equilibrium when the concentrations of reactants and products remain constant over time.

According to Le Chatelier's Principle, changes in conditions (like temperature or pressure) can disturb the equilibrium and cause the system to adjust.

  • Temperature: For the exothermic oxidation of SO₂, increasing temperature will shift the equilibrium towards the reactants (SO₂ and O₂). Decreasing temperature favors the formation of the product SO₃.
  • Pressure: The reaction involves a decrease in the number of gas molecules (from 3 moles to 2 moles). Increasing the pressure shifts the equilibrium towards the side with fewer gas molecules, favoring the formation of SO₃.

Thus, to maximize SO₃ yield, lower the temperature and increase the pressure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(\Lambda\) saturated solution of \(\mathrm{II}_{2} \mathrm{~S}\) in \(0.1 \mathrm{M} \mathrm{IICl}\) at \(25^{\circ} \mathrm{C}\) contains a \(\mathrm{S}^{2-}\) ion concentration of \(10^{-23} \mathrm{~mol} \mathrm{~L}^{-1}\). The solubility products of some sulphidcs are: \(\mathrm{CuS}=10^{-44}\), \(\mathrm{FeS}=10^{-14} ; \mathrm{MnS}=10^{-15}\) and \(\mathrm{CdS}=10^{-25} .\) If \(0.01 \mathrm{M}\) solutions of these salts in \(1 \mathrm{M}\) IICl are saturated with \(\mathrm{H}_{2} \mathrm{~S}\), which of these will be precipitated? (1) All (2) All except MnS (3) All except MnS and FeS (4) Only CuS

If the cquilibrium constants of the following cquilibrium \(\mathrm{SO}_{3} \rightleftharpoons \mathrm{SO}_{2}+\mathrm{O}_{2}\) and \(\mathrm{SO}_{2} \mid \mathrm{O}_{2} \rightleftharpoons \mathrm{SO}_{3}\) are given by \(\mathrm{K}_{\mathrm{l}}\) and \(\mathrm{K}_{2}\), respectively, which relation is corrcct? (1) \(\mathrm{K}_{1}=\left(1 / \mathrm{K}_{2}\right)^{2}\) (2) \(\mathrm{K}_{2}=\left|1 / \mathrm{K}_{\mathrm{l}}\right|^{2}\) (3) \(K_{1}=1 / K_{2}\) (4) \(\mathrm{K}_{1}=\left(\mathrm{K}_{2}\right)^{2}\)

The ionization constant of a base is \(\frac{1}{10} .\) The base is described as (1) Normal base (2) Strong basc (3) Weak base (4) None of these

Which onc of the following is not a postulate of Ostwald's theory of indicators? (1) The colour of an indicator in solution is duc to the ions furnished by it (2) The colour of an indicator is duc to the ions furnished by acidic substancc (3) \Lambdall indicators are weak acids or bases (4) \Lambdacidic indicators show decp colour in acidic solutions and vice versa

In a buffer solution consisting of a weak acid and its salt, the ratio of concentration of salt to acid is increased 10 fold, then the \(\mathrm{pH}\) of the solution will (1) increase by one (2) increase by 10 fold (3) decrease by one (4) decrease by 10 fold

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free