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The gastric juice in our stomach contains cnough hydrochloric acid to make the hydrogen ion concentration about \(0.01\) mole/litre. The pII of the gastric juice is (1) \(0.01\) (2) 1 (3) 2 (4) 14

Short Answer

Expert verified
The pH of the gastric juice is 2.

Step by step solution

01

Understand the concept of pH

The pH of a solution is a measure of the hydrogen ion concentration in that solution. It is calculated using the formula: \[ \text{pH} = -\text{log}_{10}[\text{H}^+] \]
02

Identify the hydrogen ion concentration

The concentration of hydrogen ions \( [\text{H}^+] \) in the gastric juice is given as \(0.01 \) mole/litre.
03

Calculate the pH

Substitute the hydrogen ion concentration into the pH formula: \[ \text{pH} = - \text{log}_{10}(0.01) \] Solve the logarithm: \[ \text{pH} = - \text{log}_{10}(10^{-2}) = 2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hydrogen ion concentration
The hydrogen ion concentration \([\text{H}^+]\) tells us how acidic or basic a solution is. Acidic solutions have many hydrogen ions, while basic ones have fewer.Understanding this concentration is crucial for various fields of science. Hydrogen ion concentration is measured in moles per liter (mol/L). This unit helps us see how many moles of hydrogen ions are in one liter of the solution.For example, if the hydrogen ion concentration of gastric juice is \(0.01\) mol/L, it means there are \(0.01\) moles of hydrogen ions in every liter of gastric juice.This concentrated presence of hydrogen ions contributes to the acidic nature of gastric juice and is crucial for its role in digestion.
gastric juice chemistry
Gastric juice is a mixture of substances produced by the stomach lining. It contains hydrochloric acid (HCl), making it highly acidic.Thanks to this acidity, gastric juice helps break down food and kill bacteria. The concentration of hydrogen ions in gastric juice is relatively high compared to other bodily fluids.In the given exercise, the hydrogen ion concentration is \(0.01\) mol/L. This acidity level assists in the digestion of proteins by activating digestive enzymes.More importantly, understanding the pH of gastric juice can help diagnose and treat various stomach-related issues.
logarithms in chemistry
Logarithms are fundamental in chemistry, especially when dealing with pH calculations. pH is defined as the negative logarithm (base \(10\)) of the hydrogen ion concentration: \[ \text{pH} = - \text{log}_{10}[\text{H}^+] \]This formula helps convert the often tiny hydrogen ion concentrations into manageable numbers. When the hydrogen ion concentration is \(0.01 M\), the pH is calculated as: \[ \text{pH} = - \text{log}_{10}(0.01) \] \[ \text{pH} = -(-2) = 2 \]This calculation shows the power of logarithms in simplifying complex chemical measurements. Linking logarithms to real-life concepts, like the acidity of gastric juice, can make chemistry both practical and relatable.

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Most popular questions from this chapter

Consider the reaction \(\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\) \(\mathrm{CO}_{2}(\mathrm{~g})\) in a closed container at equilibrium. At a fixed temperature what will be the effect of adding more \(\mathrm{CaCO}_{3}\) on the equilibrium concentration of \(\mathrm{CO}_{2} ?\) (1) it increases (2) it decreases (3) it remains same (4) cannot be predicted unless the values of \(K_{p}\) is known

Why only \(\Lambda \mathrm{s}^{3+}\) gets precipitated as \(\Lambda \mathrm{s}_{2} \mathrm{~S}_{3}\) not \(\mathrm{Zn}^{2-}\) as \(\mathrm{ZnS}\) when \(\mathrm{II}_{2} \mathrm{~S}\) is passed through an acidic solution containing \(\Lambda s^{3-}\) and \(Z n^{2-}\) ? (1) Solubility product of \(\mathrm{As}_{2} \mathrm{~S}_{3}\) is less than that of \(\mathrm{ZnS}\) (2) Enough As s' are present in the acidic medium (3) Zinc salt does not ionize in the acidic medium (4) Solubility product changes in the presence of an acid

Oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) by \(\mathrm{O}_{2}\) is an cxothermic reaction. The yicld of \(\mathrm{SO}_{3}\) will be maximum when(1) Temperature is increased and pressure is kept constant. (2) Temperature is reduced and pressure is increased. (3) Both temperature and pressure are increased. (4) Both temperature and pressure are reduced.

Which of the following mixture can act as a buffer solution? (1) I litre of \(0.2 \mathrm{~N} \mathrm{CH}_{3} \mathrm{COOH}+1\) litre of \(0.2 \mathrm{~N} \mathrm{NaOH}\) (2) I litre of \(0.1 \mathrm{~N} \mathrm{CH}_{3} \mathrm{COOH}+1\) litre of \(0.2 \mathrm{~N} \mathrm{NaOH}\) (3) 1 litre of \(0.2 \mathrm{~N} \mathrm{CH}_{3} \mathrm{COOH}+1\) litre of \(0.1 \mathrm{~N} \mathrm{NaOH}\) (4) All the above

The \(10^{4} \mathrm{Ka}\) values for the acids acetic, hydrofluoric, formic and nitrous are \(6.7,4.5,1.8\) and \(0.18\) but not in the correct order. The correct acid strengths arc (1) \(\mathrm{HF}=0.18, \mathrm{HNO}_{2}=1.8, \mathrm{HCOOH}=4.5\), \(\mathrm{CH}_{3} \mathrm{COOH}=6.7\) (2) \(\mathrm{HF}=6.7, \mathrm{HNO}_{2}=4.5, \mathrm{HCOOH}=1.8, \mathrm{CH}_{3} \mathrm{COOH}\) \(=0.18\) (3) \(\mathrm{HF}=1.8, \mathrm{HNO}_{2}=0.18, \mathrm{HCOOH}=4.5\), \(\mathrm{CH}_{3} \mathrm{COOH}=6.7\) (4) \(\mathrm{HF}=6.7, \mathrm{HNO}_{2}=0.18, \mathrm{HCOOH}=4.5\) \(\mathrm{CH}_{3} \mathrm{COOH}=1.8\)

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